char

问题 I wrote a code in C, which ran perfectly, I translated it to C++ . There it was giving wrong output. I had an iteration where I used both the input and the iterator variable as char to save space. But didn't behaved as expected. unsigned char repeat, i; cin >> repeat; for(i= 0; i < repeat; i++) What is the equivalent line for scanf("%hhi", &repeat) ? 回答1: Why char is not taken as numeral in C++? Because C and C++ are different programming languages. See for example n3337, a draft C++ standard

问题 I wrote a code in C, which ran perfectly, I translated it to C++ . There it was giving wrong output. I had an iteration where I used both the input and the iterator variable as char to save space. But didn't behaved as expected. unsigned char repeat, i; cin >> repeat; for(i= 0; i < repeat; i++) What is the equivalent line for scanf("%hhi", &repeat) ? 回答1: Why char is not taken as numeral in C++? Because C and C++ are different programming languages. See for example n3337, a draft C++ standard

问题 I have a char array and I need to get the address of each element. cout << &charArray gives me a valid address, However if I try to get the address of a specific element, it spits out garbage: cout << &charArray[0] 回答1: std::cout << (void*) &charArray[0]; There's an overload of operator<< for char* , that tries to print the nul-terminated string that it thinks your pointer points to the first character of. But not all char arrays are nul-terminated strings, hence the garbage. 回答2: You can do

问题 I have a char array and I need to get the address of each element. cout << &charArray gives me a valid address, However if I try to get the address of a specific element, it spits out garbage: cout << &charArray[0] 回答1: std::cout << (void*) &charArray[0]; There's an overload of operator<< for char* , that tries to print the nul-terminated string that it thinks your pointer points to the first character of. But not all char arrays are nul-terminated strings, hence the garbage. 回答2: You can do

问题 Got the error "Unclosed Character Literal" , using BlueJ, when writing: class abc { public static void main(String args[]) { String y; y = 'hello'; System.out.println(y); } } But I can't figure out what is wrong. Any idea? Thanks. 回答1: In Java, single quotes can only take one character, with escape if necessary. You need to use full quotation marks as follows for strings: y = "hello"; You also used System.out.println(g); which I assume should be System.out.println(y); Note: When making char

问题 Can I pass a negative int in printf while printing through format specifier %c since while printing int gets converted into an unsigned char? Is printf("%c", -65); valid? — I tried it on GCC but getting a diamond-like character(with question-mark inside) as output. Why? 回答1: Absolutely yes, if char is a signed type. C allows char to be signed or unsigned and in GCC you can switch between them with -funsigned-char and -fsigned-char. When char is signed it's exactly the same thing as this char

问题 I've been trying to execute the following code.. However, I keep getting the same errors over and over again and I don't know why! My code: #include <stdio.h> #include <stdlib.h> #include <time.h> #include <string.h> int main(void){ int randomNum; char takenWords[4]; char words[20]={"DOG", "CAT", "ELEPHANT", "CROCODILE", "HIPPOPOTAMUS", "TORTOISE", "TIGER", "FISH", "SEAGULL", "SEAL", "MONKEY", "KANGAROO", "ZEBRA", "GIRAFFE", "RABBIT", "HORSE", "PENGUIN", "BEAR", "SQUIRREL", "HAMSTER"}; srand

问题 http://docs.oracle.com/javase/tutorial/java/nutsandbolts/datatypes.html, char size is 16 bit i.e 2 byte. somehow i recalled its 8 bit i.e 1 byte. To clear my doubt, i created a text file with single character "a" and saved it. Then i inspected the size of file , its 1 byte i.e 8 bit. I am confused whats the size of character ? If its 2 byte , why file size is 1 byte and if it is 1 byte why link says 2 bytes? 回答1: A char in Java is a UTF-16 code unit. It's not necessarily a complete Unicode

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed last month . I want to merge two characters and print them via a single variable by using ASCII (refer to the image below): [1]: https://i.stack.imgur.com/TWodP.jpg 回答1: try this if your machine is little endian unsigned int C = (b << 8) | a; printf("%s",&C); otherwise if your machine is big endian try unsigned

问题 This question already has answers here : Will a `char` always-always-always have 8 bits? (7 answers) Closed 4 years ago . That's all. Didn't find any similar topic so bear with me it there is. 回答1: From a copy of the ANSI C specification, see Section 3.1.2.5 - Types : An object declared as type char is large enough to store any member of the basic execution character set. If a member of the required source character set enumerated in $2.2.1 is stored in a char object, its value is guaranteed