chain

Look up a key in a chain of Python dicts?

由 ≯℡__Kan透↙ 提交于 2019-12-11 06:36:31
问题 Is there a built-in way in Python to look up a key k in a dict d and, if the key is not present, look it up instead in another dict e ? Can this be extended to an arbitrarily long chain of dict s d => e => f => ...? 回答1: You could use a collections.ChainMap: from collections import ChainMap d = ChainMap({'a': 1, 'b': 2}, {'b': 22}, {'c': 3}) print(d['c']) print(d['b']) This would output: 3 2 Notice that the lookup for key 'b' was satisfied by the first dictionary in the map and the remaining

Switching between filter chains using GPUImage Framework

由 戏子无情 提交于 2019-12-10 11:02:26
问题 I would like to switch between two filter chains as shown in case 1 and case 2 with the code below. When I initially select either cases, the output appears correct. However, when I switch to another the filter chain, the output flickers between current and prior filter chain. What is the recommended way to switch filter chains? -(void) updateFilter:(NSInteger) style { switch (style) { case 1: [kuwahara setRadius:5]; [videoCamera addTarget:kuwahara]; [kuwahara addTarget:grayscale]; [grayscale

python celery: How to append a task to an old chain

由 隐身守侯 提交于 2019-12-10 10:15:34
问题 I keep in my database, the reference to a chain. from tasks import t1, t2, t3 from celery import chain res = chain(t1.s(123)|t2.s()|t3.s())() res.get() How can I append an other task to this particular chain ? res.append(t2.s()) My goal is to be sure that chains are executed in the same order I specified in my code. And if a task fail in my chain, the following tasks are not executed. For know I'm using super big tasks in a specify queue. 回答1: All the information is contained in the message.

Promise: Ignore Catch and Return to Chain

由 流过昼夜 提交于 2019-12-10 01:25:11
问题 Is it possible to ignore a catch and return back to the chain? promiseA() // <-- fails with 'missing' reason .then(promiseB) // <-- these are not going to run .then(promiseC) .catch(function(error, ignore){ if(error.type == 'missing'){ ignore() // <-- ignore the catch and run promiseB and promiseC } }) Is something like this possible? 回答1: Here's the synchronous analogy: try { action1(); // throws action2(); // skipped action3(); // skipped } catch (e) { // can't resume } vs try { action1();

Method chaining without parentheses, how to?

由 本小妞迷上赌 提交于 2019-12-08 05:09:29
I would like to do a method chain, for example like this: Car myCar = new Car(); // Chaining myCar.config.engine.cylinders("4"); But how do I do the chaining, without using parentheses in "config" or "engine"? I can only figure out to do it like this: myCar.config().engine().cylinders("4"); Dethariel You can do this by declaring Config property in your Car class. Then Engine property in CarConfig class, like this: public class Car { public CarConfig Config { get; set; } } Then you can chain the calls. You could use properties as many suggest, but this whole thing stinks of breaking the Law of

Nginx not serving intermediate certificate

由 孤者浪人 提交于 2019-12-08 04:46:31
问题 I am trying to install an ssl certificate on Nginx (laravel forge actually). I have concatenated the certificate with the intermediate and I don't get any errors in the Nginx error log. However it is not trusted in mobile chrome - only desktops. Looking at Qualys ssl test, it's says that the Chain is incomplete. I don't see how though. Here's my Nginx config server { listen 80; server_name **********.com; return 301 https://**********.com$request_uri; } server { listen 443 ssl; server_name **

Can I combine multiple certs into one without the private key?

由 元气小坏坏 提交于 2019-12-07 23:58:31
问题 I need to have up to date cert trust stores in many devices, so I would like to be able to combine them into on cert that I can then just push that one file. I only want to bundle the public keys of the many CA's but I do not want to add the private file because I want a cert that I push to all of my devices. I was thinking that this feature was called a chain but openssl will not take the command without a private file. Can this be done? I have tried several different things and I have

Returning data from Parse promise chain

由 孤街醉人 提交于 2019-12-07 16:02:15
问题 I think I have got my head around Parse promise chains, but what I don't understand is how I return my data from the functions (i) back up the promise chain and (ii) back to the calling method of my original JS code. Using the code below, the first Parse query is called, then a() and finally b() which is all fine. The console.log at each stage are for test purposes and show that the chains have been executed and in order. I now have 3 questions: How do I get the data back from function a()

Switching between filter chains using GPUImage Framework

由 跟風遠走 提交于 2019-12-06 07:11:29
I would like to switch between two filter chains as shown in case 1 and case 2 with the code below. When I initially select either cases, the output appears correct. However, when I switch to another the filter chain, the output flickers between current and prior filter chain. What is the recommended way to switch filter chains? -(void) updateFilter:(NSInteger) style { switch (style) { case 1: [kuwahara setRadius:5]; [videoCamera addTarget:kuwahara]; [kuwahara addTarget:grayscale]; [grayscale addTarget:filteredVideoView]; break; case 2: [videoCamera addTarget:grayscale]; [blur setBlurSize:3];

Returning data from Parse promise chain

由 女生的网名这么多〃 提交于 2019-12-05 22:10:48
I think I have got my head around Parse promise chains, but what I don't understand is how I return my data from the functions (i) back up the promise chain and (ii) back to the calling method of my original JS code. Using the code below, the first Parse query is called, then a() and finally b() which is all fine. The console.log at each stage are for test purposes and show that the chains have been executed and in order. I now have 3 questions: How do I get the data back from function a() and function b() so I can access it in the main function getUserCompetitionTokens()? How do I return any
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