cartesian-product

C++ cartesian product of multiple strings

我与影子孤独终老i 提交于 2020-01-17 01:38:08
问题 I have strings stored in a vector as such: vector<string> ex = {"ab", "cd", "ef"} . Now I need to create the cartesian product of these strings (number of strings in the vector, nor the length of the strings is fixed!). The result should be: ace acf ade adf bce bcf bde bdf Is there a build-in function that exists already for this, or do you have any advice how to perform the implementation? The single letters of the strings should be used for the cartesian product not the entire string! 回答1:

Cartesian power - via recursion

生来就可爱ヽ(ⅴ<●) 提交于 2020-01-15 09:32:05
问题 The original question is here: Cartesian power (a special Cartesian product) -- choose elements from array, in repeatable style In the old question, there are already answers gave a solution via iteration. I am wondering is there a recursive solution, similar as the solution from following link, which print permutations with recursion: https://www.geeksforgeeks.org/write-a-c-program-to-print-all-permutations-of-a-given-string/ Currently I have wrote following program, which is not correct yet

Cartesian power - via recursion

旧巷老猫 提交于 2020-01-15 09:31:44
问题 The original question is here: Cartesian power (a special Cartesian product) -- choose elements from array, in repeatable style In the old question, there are already answers gave a solution via iteration. I am wondering is there a recursive solution, similar as the solution from following link, which print permutations with recursion: https://www.geeksforgeeks.org/write-a-c-program-to-print-all-permutations-of-a-given-string/ Currently I have wrote following program, which is not correct yet

Creating Combinations of Elements

梦想与她 提交于 2020-01-14 05:12:31
问题 I want to create product option system. I have a form look like this: Form's inputs are tag inputs. First input is option name. When you put any option name the new tag input added in the form. My problem: I can't create combinations in controller because the inputs name an quantity will be random. Current Code: I found this code but i cant customize it for my system First inputs code id: when i post data goes to controller post it another blade. i incude this in my page In controller public

How to create cartesian product over arbitrary groups of numbers in Java?

纵然是瞬间 提交于 2020-01-12 05:08:27
问题 Let's say I have 2 groups of numbers: {1, 2, 3}, {4, 5} I'd like to create an algorithm (in Java) that outputs the following 6 combinations: 1,4 1,5 2,4 2,5 3,4 3,5 There can be an arbitrary number of groups and an arbitrary number of members within each group. So in the above example, there are 2 groups with the first group having 3 members and the second group having 2 members. Another example is the following (3 groups, 3 members in first groups and 2 members in second and third groups):

How to create cartesian product over arbitrary groups of numbers in Java?

依然范特西╮ 提交于 2020-01-12 05:08:06
问题 Let's say I have 2 groups of numbers: {1, 2, 3}, {4, 5} I'd like to create an algorithm (in Java) that outputs the following 6 combinations: 1,4 1,5 2,4 2,5 3,4 3,5 There can be an arbitrary number of groups and an arbitrary number of members within each group. So in the above example, there are 2 groups with the first group having 3 members and the second group having 2 members. Another example is the following (3 groups, 3 members in first groups and 2 members in second and third groups):

cartesian product with dplyr R

ⅰ亾dé卋堺 提交于 2020-01-09 07:31:04
问题 I'm trying to find the dplyr function for cartesian product. I've two simple data.frame with no common variable: x <- data.frame(x=c("a","b","c")) y <- data.frame(y=c(1,2,3)) I would like to reproduce the result of merge(x,y) x y 1 a 1 2 b 1 3 c 1 4 a 2 5 b 2 6 c 2 7 a 3 8 b 3 9 c 3 I've already looked for this (for example here or here) without finding anything useful. Thank you very much 回答1: Use crossing from the tidyr package: x <- data.frame(x=c("a","b","c")) y <- data.frame(y=c(1,2,3))

itertools product to generate all possible strings of size 3

醉酒当歌 提交于 2020-01-06 13:06:45
问题 Input: pos_1= 'AVNMHDRW' pos_2= 'KNTHDYBW' pos_3= 'KVNGSDRB' Trying to find all possible triplets using one item from pos_1, one from pos_2, and one from pos_3 I'm trying to figure out how to use itertools.product(*) but I'm a little confused Ultimately, I want to create a list (or generator object) of all the different possibilities by taking one from pos_1 then one from pos_2 and then one from pos_3 Example output: 'AKK','ANV','WWB' pos_1 stands for position one and so on for pos_2 and pos

itertools product to generate all possible strings of size 3

ε祈祈猫儿з 提交于 2020-01-06 13:04:23
问题 Input: pos_1= 'AVNMHDRW' pos_2= 'KNTHDYBW' pos_3= 'KVNGSDRB' Trying to find all possible triplets using one item from pos_1, one from pos_2, and one from pos_3 I'm trying to figure out how to use itertools.product(*) but I'm a little confused Ultimately, I want to create a list (or generator object) of all the different possibilities by taking one from pos_1 then one from pos_2 and then one from pos_3 Example output: 'AKK','ANV','WWB' pos_1 stands for position one and so on for pos_2 and pos

Jaccard Similarity of an RDD with the help of Spark and Scala without Cartesian?

≯℡__Kan透↙ 提交于 2020-01-03 02:21:11
问题 I am working on pair RDDs. My aim is to calculate jaccard similarity between the set of rdd values and cluster them according to the jaccard similarity threshold value.Structure of my RDD is : val a= [Key,Set(String)] //Pair RDD For example:- India,[Country,Place,....] USA,[Country,State,..] Berlin,[City,Popluatedplace,..] After finding jaccard similarity, I will cluster the similar entities into one cluster. In the above example, India and USA will be cluster into one cluster based on some