cartesian-coordinates

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 11 months ago . Improve this question How to convert pixel/screen coordinates to cartesian coordinates(x,y)? The info I have on the pictures is (see image): vFov in degrees, hFov in degrees, pixel width, pixel height Basically what I want is to take any pixel on the image, and calculate the relative degrees it

问题 Trying to plot a network with the ggraph package and specify the coordinates of each node. While I can implement this with the igraph package - I cannot do this with the ggraph package. # reproducible example to generate a random graph library(igraph) g1 <- erdos.renyi.game(20, 1/2) plot(g1) # function to produce coordinates for each node in order of the node # degree (number of links per node) coord <- function(g){ n.nod <- length(V(g)) mat.c <- matrix(0, nrow = n.nod, ncol = 2) deg <-

问题 Trying to plot a network with the ggraph package and specify the coordinates of each node. While I can implement this with the igraph package - I cannot do this with the ggraph package. # reproducible example to generate a random graph library(igraph) g1 <- erdos.renyi.game(20, 1/2) plot(g1) # function to produce coordinates for each node in order of the node # degree (number of links per node) coord <- function(g){ n.nod <- length(V(g)) mat.c <- matrix(0, nrow = n.nod, ncol = 2) deg <-

问题 Trying to plot a network with the ggraph package and specify the coordinates of each node. While I can implement this with the igraph package - I cannot do this with the ggraph package. # reproducible example to generate a random graph library(igraph) g1 <- erdos.renyi.game(20, 1/2) plot(g1) # function to produce coordinates for each node in order of the node # degree (number of links per node) coord <- function(g){ n.nod <- length(V(g)) mat.c <- matrix(0, nrow = n.nod, ncol = 2) deg <-

问题 Trying to plot a network with the ggraph package and specify the coordinates of each node. While I can implement this with the igraph package - I cannot do this with the ggraph package. # reproducible example to generate a random graph library(igraph) g1 <- erdos.renyi.game(20, 1/2) plot(g1) # function to produce coordinates for each node in order of the node # degree (number of links per node) coord <- function(g){ n.nod <- length(V(g)) mat.c <- matrix(0, nrow = n.nod, ncol = 2) deg <-

问题 Trying to plot a network with the ggraph package and specify the coordinates of each node. While I can implement this with the igraph package - I cannot do this with the ggraph package. # reproducible example to generate a random graph library(igraph) g1 <- erdos.renyi.game(20, 1/2) plot(g1) # function to produce coordinates for each node in order of the node # degree (number of links per node) coord <- function(g){ n.nod <- length(V(g)) mat.c <- matrix(0, nrow = n.nod, ncol = 2) deg <-

问题 Trying to plot a network with the ggraph package and specify the coordinates of each node. While I can implement this with the igraph package - I cannot do this with the ggraph package. # reproducible example to generate a random graph library(igraph) g1 <- erdos.renyi.game(20, 1/2) plot(g1) # function to produce coordinates for each node in order of the node # degree (number of links per node) coord <- function(g){ n.nod <- length(V(g)) mat.c <- matrix(0, nrow = n.nod, ncol = 2) deg <-

问题 I'm trying to create a cartesian coordinate system (i.e. for coordinate geometry) using chart.js. The documentation actually states "cartesian axes" but I'm not seeing any evidence that such a name is warranted. My chart is as follows: <canvas id="myChart" width="400" height="400"></canvas> <script> var ctx = document.getElementById('myChart').getContext('2d'); var scatterChart = new Chart(ctx, { type: 'scatter', data: { datasets: [{ label: 'Scatter Dataset', data: [{x:-3,y:5},{x:-2,y:0},{x:

问题 I'm looking for a way to plot a corrugated circle in Python. My attempt doesn't produce the correct output: from matplotlib import pyplot as plt import numpy as np from math import pi x=np.linspace(-10,10,100) y=x X, Y = np.meshgrid(x,y) circle = (X-np.cos(2*pi*0.2*Y))**2 + (Y-np.sin(2*pi*0.2*X))**2 - 5. plt.contour(X,Y,circle,[0]) plt.show() theta = np.linspace(-pi,pi,100) courbure = np.sin(theta*10) plt.plot(theta,courbure) plt.show() circle2 = (X-(courbure*np.cos(theta)))**2 + (Y-np.sin

问题 i have an assignment on sympy and am struggling with the following question: "Prove with the help of Sympy that 4*(x 2 + y 2 -ax) 3 = 27 a 2 (x 2 +y 2 ) 2 can be written using r = 4a*cos(theta/3) 3 ". I have tried to substitute x = r*cos(theta) and y = r*sin(theta) . Then I tried sp.solveset(eq, r) but I only got a very longset of {}, nothing like the given polar equation. Does anyone know how to do this (I can use sympy and numpy)? 回答1: The following code builds the equation from its left