Call php function from bash - with arguments
问题 I have a simple func.php file with concat function: <?php function concat($arg1, $arg2) { return $arg1.$arg2; } ?> I would like to call this function from linux bash shell with two arguments : 1st: "Hello, " 2nd: "World!" and print the output ("Hello, World!") to linux bash shell. Please tell me, how to do it? 回答1: What you want is $argv So for example, your script would be called like this: php /path/to/script.php 'Hello, ' 'World!' Then in your PHP file: <?php $arg1 = $argv[1]; $arg2 =