calculation

Using parantheses around variables in Javascript to change priority in math calculations

可紊 提交于 2019-12-14 03:05:18
问题 I'm exercising in javascript calculations using a combination of maths and variables and i'm finding a difficulty on using the right way parentheses. For example i want to do the following calculation [(4,95/ans2)-4,5]*100 where ans2 is a calculated variable. In the last field i get 45.000 and i should take - 4.046 ... if the input in the first and second fields was 2 + 2 <form name="Calcultor" Method="Get" id='form1'>First Number: <input type="text" name="first" size="35" id="first">+ Second

Excel - Multiple Cell Calculation

为君一笑 提交于 2019-12-13 10:24:43
问题 I'm a teacher and trying to create a mark sheet the problem I have is that assignments are marked using different schemes (i.e. % [1 - 100], Level [1 -4], Letter Grade [F - A]). The problem I have is that I only want to report using one marking scheme and need to convert or calculate the other marking schemes based on the scheme there is it is marked. I've made an excel worksheet which contains a student names and assignments. The sheet then has 3 other columns, one representing each scheme

Calculate time length based on two given times

守給你的承諾、 提交于 2019-12-12 05:39:46
问题 Need help to calculate $work_in_daytime and $work_in_nighttime . $nightStart = '22:00'; $nightEnd = '07:00'; $workers = array( '0' => array( 'name' => 'Lyons', 'start' => '15:15', 'end' => '23:45' ), '1' => array( 'name' => 'Santos', 'start' => '10:00', 'end' => '22:00' ), '2' => array( 'name' => 'Montgomery', 'start' => '22:30', 'end' => '08:00' ) ); foreach ($workers as $worker) { $length_of_work = abs(strtotime($worker['start']) - strtotime($worker['end'])) / 3600; $work_in_daytime = '';

Android Divide number with decimal fraction

坚强是说给别人听的谎言 提交于 2019-12-12 04:54:45
问题 How can i check number is divisible by particular number or not both numbers are decimal. with decimal point value of two digits. i had tried with below (((dn / size) % 1) == 0) but in some cases it not provide proper out put. how can i resolve it. here i put some example values like double dn = 369.35,369.55.370.55 and size may be 0.05,0.10,0.5 etc... if(((dn / size) % 1) == 0) { Log.d(TAG,"OK"); } else { Log.d(TAG,"OK"); } please help me to short out it. 回答1: (dn / size) % 1 == 0 whilst

MySQL query to get total percentage change

戏子无情 提交于 2019-12-11 17:19:49
问题 How to add a column of percent change (not percentage points) in MySQL? there is a table with column of changes in percents: +---------+ | percent | +---------+ | -0.50 | | 0.50 | | 1.00 | | -0.20 | | 0.50 | | -1.00 | | -2.00 | | 0.75 | | 1.00 | | 0.50 | +---------+ How to write a query that calculates a total percent change of a value for each row so the calculated row expresses its percentage change and all previous rows of percentage change?. expected result: +---------+---------------+---

Is there any way to convert a sum of numbers back to enum? [duplicate]

随声附和 提交于 2019-12-11 16:31:17
问题 This question already has answers here : What does the [Flags] Enum Attribute mean in C#? (11 answers) Using a bitmask in C# (6 answers) Closed 4 months ago . So there are some mods in a game called osu and when I call the api for any plays I get back a sum of the mod's number (like 72). However, I can't think of any way to convert that back to the original enum names. I tried this way: (Mods)enabled_mods , but this only turned back the number. enum Mods { None = 0, NoFail = 1, Easy = 2,

How to add months and days for a simple interest-rate calculation (Java)

梦想与她 提交于 2019-12-11 16:24:58
问题 I am working on a program for an assignment. There I got stuck on how to add the days and months for my program. I can already convert the simple interest into years , but not for months and days: import java.util.Scanner; public class SimpleInterest { public static void main(String[] args) { double PAmount, ROI, TimePeriod, simpleInterset; Scanner scanner = new Scanner(System.in); System.out.print(" Please Enter the Principal Amount : "); PAmount = scanner.nextDouble(); System.out.print("

Best way(run-time) to aggregate (calculate ratio of) sum to total count based on group by

若如初见. 提交于 2019-12-11 12:57:20
问题 I'm trying to identify ratio of approved applications(identified by flag '1' and if not then '0') to total applications for each person(Cust_ID). I have achieved this logic by the following code but it takes about 10 mins to compute this for 1.6 M records. Is there a faster to perform the same operation? # Finding ratio of approved out of total applications df_approved_ratio = df.groupby('Cust_ID').apply(lambda x:x['STATUS_Approved'].sum()/len(x)) 回答1: I think need aggregate by mean : df = pd

Calculating interest across multiple interest rates

醉酒当歌 提交于 2019-12-11 06:48:12
问题 I have a table where I store interest rates, each with a start date where it became applicable. Later-dated entries in the table supersede earlier entries. I have to query this table with a start date, an end date, and an amount. From these values I need to end up with an overall interest amount that takes the different interest rates for the date span into account. CREATE TABLE [dbo].[Interest_Rates]( [Interest_Rate] [float] NULL, [Incept_Date] [datetime] NULL ) ON [PRIMARY] GO I have four

R: How to calculate the difference in years between a date and a year

爷,独闯天下 提交于 2019-12-11 05:54:42
问题 Is there a quick way to calculate the difference in years between a) a date (data$First.Trading.Day) eg. "2016-02-09" and b) a year (data$Founding.Year) e.g. "1999" I already did the following, but do not get to a correct result: data$Age <- difftime(data$First.Trading.Day, data$Founding.Year, "years") then I made a new column with only the year of the First trading date and tried this: data$First.Trading.Year <- format(as.Date(data$First.Trading.Day),"%Y") data$Age <- (data$First.Trading