buildconfig

I have a config.properties file under conf directory. and have a entry in the above file like this: grails.tomcat.version = 2.2.4 . How can I use this value in BuildConfig.groovy file? Suppose: plugins = { build ":tomcat:{here i want to use the config value}" } You can do read the properties file as below: plugins { def props = new Properties() new File("grails-app/conf/config.properties").withReader{ props.load(it) } def slurp = new ConfigSlurper().parse(props) build ":tomcat:$slurp.grails.tomcat.version" } I do not see a value out of it if you only have that single entry to use from the

is there a way in c# to use a custom Configuration like "#if DEBUG" I need a "#if OFFLINE" as my Build-Config's name is "Offline" (only for further debug-purposes too)... Thanks! Build -> Configuration manager -> Active solution configuration -> New... Create a new configuration "Offline". Project -> Properties -> Build -> Configuration -> Offline Conditional compilation symbols: type OFFLINE Save project. Yes, you can. But before you can, follow these steps: In Visual Studio, go to Properties -> Build. At the configuration dropdown, select "Offline" Add "OFFLINE" to the "Conditional

I am using Gradle to build my Android application. I am trying to use some flags based on the build type (release or debug). My Gradle file looks like this: android { buildTypes { debug { buildConfigField 'boolean', 'PREPROD', 'true' buildConfigField 'boolean', 'STAGING', 'false' } release { buildConfigField 'boolean', 'PREPROD', 'false' buildConfigField 'boolean', 'STAGING', 'false' } } } And if I try to call BuildConfig.PREPROD or BuildConfig.STAGING I get a "Cannot resolve symbol" error. The Gradle sync was successful, so I don't know if I forgot some steps in order to be able to use this

I am programming Android applications, and the best way here may or may not be the same as Java in general. I simply want to be able to set a debug flag that will only execute certain portions of code when it's set to true––equiv to C++ setting a preprocessor #define DEBUG and using #ifdef DEBUG. Is there an accepted or best way to accomplish this in Java? Right now I'm just going to set a variable in my Application object, but I don't imagine this is the best way. That's the way I do it: // in some.class.with.Constants public static final boolean DEV_MODE = true; // in some other class import