bson

Name clash of two different bson modules - How can I use both pymongo's bson module and bson's bson module in the same script?

和自甴很熟 提交于 2021-02-11 17:11:27
问题 How to avoid the name clash of pymongo's bson module and bson's (py-bson on GitHub) bson module? 回答1: Install bson package as pybson , see https://github.com/py-bson/bson/issues/70. I have used pip uninstall bson and pip install pybson now so that I can use import pybson as bson when I want the old name back. If I accidentally need both pymongo 's and pybson 's import bson , I can use aliases. 来源: https://stackoverflow.com/questions/63068007/name-clash-of-two-different-bson-modules-how-can-i

Name clash of two different bson modules - How can I use both pymongo's bson module and bson's bson module in the same script?

旧时模样 提交于 2021-02-11 17:11:26
问题 How to avoid the name clash of pymongo's bson module and bson's (py-bson on GitHub) bson module? 回答1: Install bson package as pybson , see https://github.com/py-bson/bson/issues/70. I have used pip uninstall bson and pip install pybson now so that I can use import pybson as bson when I want the old name back. If I accidentally need both pymongo 's and pybson 's import bson , I can use aliases. 来源: https://stackoverflow.com/questions/63068007/name-clash-of-two-different-bson-modules-how-can-i

Name clash of two different bson modules - How can I use both pymongo's bson module and bson's bson module in the same script?

假如想象 提交于 2021-02-11 17:10:52
问题 How to avoid the name clash of pymongo's bson module and bson's (py-bson on GitHub) bson module? 回答1: Install bson package as pybson , see https://github.com/py-bson/bson/issues/70. I have used pip uninstall bson and pip install pybson now so that I can use import pybson as bson when I want the old name back. If I accidentally need both pymongo 's and pybson 's import bson , I can use aliases. 来源: https://stackoverflow.com/questions/63068007/name-clash-of-two-different-bson-modules-how-can-i

Necessity of bson struct tag when using with MongoDB go client

本小妞迷上赌 提交于 2021-02-11 15:31:40
问题 I am watching a tutorial on how to create Go restful APIs that use MongoDB for persistence (this one to be more precise). The instructor is using in his model (struct) both json and bson tags, something like type NoteUpdate struct { ID string `json:"id,omitempty" bson:"_id,omitempty"` Title string `json:"title" bson:"title,omitempty"` Content string `json:"content" bson:"content,omitempty"` ChangedAt int64 `json:"changed_at" bson:"changed_at"` } However the official go driver example does not

Necessity of bson struct tag when using with MongoDB go client

别来无恙 提交于 2021-02-11 15:30:22
问题 I am watching a tutorial on how to create Go restful APIs that use MongoDB for persistence (this one to be more precise). The instructor is using in his model (struct) both json and bson tags, something like type NoteUpdate struct { ID string `json:"id,omitempty" bson:"_id,omitempty"` Title string `json:"title" bson:"title,omitempty"` Content string `json:"content" bson:"content,omitempty"` ChangedAt int64 `json:"changed_at" bson:"changed_at"` } However the official go driver example does not

MongoDB Compass Filter expression to Go bson.M expression

南楼画角 提交于 2021-02-11 12:35:46
问题 I have a filter on MongoDB Compass filter Between two dates and an string of two posible values like this code: {closed_at: {$gt: ISODate('2020-07-01T00:00:00.700+00:00'),$lt: ISODate('2020-07-30T00:00:00.700+00:00')}, status: { $in: ["paid", "delivered"] }} (I expect the same 1256 Documents if filter the same values on Go) Now I need to convert this filter to a valid bson.M expression, can´t find the trick for the "status" string filed, have this query expression but have an error message:

Qmgo 开源了! 更好用的 Go 语言 MongoDB driver

安稳与你 提交于 2021-02-09 06:06:18
近日,七牛研发团队开源了Qmgo[1] - Go 语言的 MongoDB driver。一经发布,便受到了「CSDN」、「Go 语言中文网」等多家媒体的报道和技术开发者们的广泛关注。Qmgo 在设计上参考了老牌的 driver Mgo[3] (比如 Mgo 的链式调用),基于Mongo 官方 driver[2]实现,但是有着更好的易用性。让我们一起深度了解这一开源项目。 背景 做 Qmgo 的初衷,来自于使用 MongoDB 的 gopher 们共同的困扰,在 MongoDB 的 Go 官方 driver 成型前(v1.0.0 发布在 2019 年 3 月),一直是 Mgo 一统江湖,出色的接口设计让其非常流行。七牛做为最早使用 Go 的公司之一,自然也是 Mgo 的深度用户。 但是 Mgo 已经在 3 年前不再维护,bug 不修复,MongoDB 的新特性自然也无法支持,而官方 driver 的接口设计是出名的不易用。 这样的背景下,基于满足下面的需求,Qmgo 诞生了 想要 MongoDB 新特性 想要更稳定的 driver 想要 Mgo 出色的接口设计 想要从 Mgo 迁移到 Qmgo,代码改动最小 下面,简单介绍一下 Qmgo 的特点,详情可以点击查看:Qmgo[4] 好用在哪里? 举一个多文件查找、sort和limit的例子, 说明qmgo和mgo的相似,以及对go

Getting Distinct values of multiple values in Mongodb

。_饼干妹妹 提交于 2021-02-07 18:17:00
问题 Let's imagine I have the following collection of books (Edited out the ID field for compactness): { "author" : "Steve Jones", "title" : "Fun Stuff", "edition" : "2010" } { "author" : "Steve Jones", "title" : "Fun Stuff", "edition" : "2011" } { "author" : "Steve Jones", "title" : "Boring Stuff", "edition" : "2010" } { "author" : "Ben Johnson", "title" : "Other Stuff", "edition" : "2010" } What should I do I want to find only the latest edition of each book? In other words: I want to get a

Getting Distinct values of multiple values in Mongodb

廉价感情. 提交于 2021-02-07 18:16:56
问题 Let's imagine I have the following collection of books (Edited out the ID field for compactness): { "author" : "Steve Jones", "title" : "Fun Stuff", "edition" : "2010" } { "author" : "Steve Jones", "title" : "Fun Stuff", "edition" : "2011" } { "author" : "Steve Jones", "title" : "Boring Stuff", "edition" : "2010" } { "author" : "Ben Johnson", "title" : "Other Stuff", "edition" : "2010" } What should I do I want to find only the latest edition of each book? In other words: I want to get a

Read/write binary data to MongoDB in Node.js

时光怂恿深爱的人放手 提交于 2021-02-07 09:15:48
问题 I've been able to successfully write binary data (an image) to MongoDB in Node.js. However I can't find clear documentation on how to read it back. Here's how I'm writing the image to MongoDB: var imageFile = req.files.myFile; var imageData = fs.readFileSync(imageFile.path); var imageBson = {}; imageBson.image = new db.bson_serializer.Binary(imageData); imageBson.imageType = imageFile.type; db.collection('images').insert(imageBson, {safe: true},function(err, data) { I'd appreciate any