break

HTML5 canvas ctx.fillText won't do line breaks?

半世苍凉 提交于 2019-11-26 23:41:04
I can't seem to be able to add text to a canvas if the text includes "\n". I mean, the line breaks do not show/work. ctxPaint.fillText("s ome \n \\n <br/> thing", x, y); The above code will draw "s ome \n <br/> thing" , on one line. Is this a limitation of fillText or am I doing it wrong? the "\n"s are there, and aren't printed, but they don't work either. Simon Sarris I'm afraid it is a limitation of Canvas' fillText . There is no multi-line support. Whats worse, there's no built-in way to measure line height, only width, making doing it yourself even harder! A lot of people have written

Python - `break` out of all loops [duplicate]

主宰稳场 提交于 2019-11-26 23:06:35
问题 This question already has answers here : How to break out of multiple loops? (29 answers) Closed 5 years ago . I am using multiple nested for loops. In the last loop there is an if statement. When evaluated to True all the for loops should stop, but that does not happen. It only break s out of the innermost for loop, and than it keeps on going. I need all loops to come to a stop if the break statement is encountered. My code: for i in range(1, 1001): for i2 in range(i, 1001): for i3 in range

Break out of a while loop using a function

怎甘沉沦 提交于 2019-11-26 22:08:56
问题 Is there any way to break out of infinite loops using functions? E.g., # Python 3.3.2 yes = 'y', 'Y' no = 'n', 'N' def example(): if egg.startswith(no): break elif egg.startswith(yes): # Nothing here, block may loop again print() while True: egg = input("Do you want to continue? y/n") example() This causes the following error: SyntaxError: 'break' outside loop Please explain why this is happening and how this can be fixed. 回答1: As far as I'm concerned you cannot call break from within example

How do I exit a while loop in Java?

只谈情不闲聊 提交于 2019-11-26 22:02:33
What is the best way to exit/terminate a while loop in Java? For example, my code is currently as follows: while(true){ if(obj == null){ // I need to exit here } } Use break : while (true) { .... if (obj == null) { break; } .... } However, if your code looks exactly like you have specified you can use a normal while loop and change the condition to obj != null : while (obj != null) { .... } while(obj != null){ // statements. } break is what you're looking for: while (true) { if (obj == null) break; } alternatively, restructure your loop: while (obj != null) { // do stuff } or: do { // do stuff

How to break out of a loop from inside a switch?

自作多情 提交于 2019-11-26 21:32:28
I'm writing some code that looks like this: while(true) { switch(msg->state) { case MSGTYPE: // ... break; // ... more stuff ... case DONE: break; // **HERE, I want to break out of the loop itself** } } Is there any direct way to do that? I know I can use a flag, and break from the loop by putting a conditional break just after the switch. I just want to know if C++ has some construct for this already. Dave Jarvis Premise The following code should be considered bad form, regardless of language or desired functionality: while( true ) { } Supporting Arguments The while( true ) loop is poor form

How to break out of while loop in Python?

回眸只為那壹抹淺笑 提交于 2019-11-26 20:09:58
问题 I have to make this game for my comp class, and I can't figure out how how break out of this loop. See, I have to play against the "computer," by rolling bigger numbers, and seeing who has the bigger score. But I can't figure out how to "break" from my turn, and transition to the computers turn. I need "Q" (quit) to signal the beginning of the computers turn, but I don't know how to do it. ans=(R) while True: print('Your score is so far '+str(myScore)+'.') print("Would you like to roll or

Nested jQuery.each() - continue/break

微笑、不失礼 提交于 2019-11-26 19:56:38
问题 Consider the following code: var sentences = [ 'Lorem ipsum dolor sit amet, consectetur adipiscing elit.', 'Vivamus aliquet nisl quis velit ornare tempor.', 'Cras sit amet neque ante, eu ultrices est.', 'Integer id lectus id nunc venenatis gravida nec eget dolor.', 'Suspendisse imperdiet turpis ut justo ultricies a aliquet tortor ultrices.' ]; var words = ['ipsum', 'amet', 'elit']; $(sentences).each(function() { var s = this; alert(s); $(words).each(function(i) { if (s.indexOf(this) > -1) {

How to break out of nested loops?

依然范特西╮ 提交于 2019-11-26 19:41:17
If I use a break statement, it will only break inner loop and I need to use some flag to break the outer loop. But if there are many nested loops, the code will not look good. Is there any other way to break all of the loops? (Please don't use goto stmt .) for(int i = 0; i < 1000; i++) { for(int j = 0; j < 1000; j++) { if(condition) { // both of the loops need to break and control will go to stmt2 } } } stmt2 What about: if(condition) { i = j = 1000;break; } No, don't spoil the fun with a break . This is the last remaining valid use of goto ;) If not this then you could use flags to break out

How do I do a “break” or “continue” when in a functional loop within Kotlin?

▼魔方 西西 提交于 2019-11-26 19:41:08
问题 In Kotlin, I cannot do a break or continue within a function loop and my lambda -- like I can from a normal for loop. For example, this does not work: (1..5).forEach { continue@forEach // not allowed, nor break@forEach } There are old documentation that mentions this being available but it appears it was never implemented. What is the best way to get the same behavior when I want to continue or break from within the lambda? Note: this question is intentionally written and answered by the

Breaking loop when “warnings()” appear in R

冷暖自知 提交于 2019-11-26 19:04:17
问题 I am having an issue: I am running a loop to process multiple files. My matrices are enormous and therefore I often run out of memory if I am not careful. Is there a way to break out of a loop if any warnings are created? It just keeps running the loop and reports that it failed much later... annoying. Any ideas oh wise stackoverflow-ers?! 回答1: You can turn warnings into errors with: options(warn=2) Unlike warnings, errors will interrupt the loop. Nicely, R will also report to you that these