break

Suppose, I have a if statement inside a for loop: for( ; ; ) { if( ) { printf(" inside if"); break; }//if printf("inside for"); }//for Now, will the break statement cause the compiler to come out of the for loop or will it only come out of the body of if once the condition in the if becomes satisfied? Windows programmer The break statement breaks out of the nearest enclosing loop or switch statement . break does not break out of an if statement, but the nearest loop or switch that contains that if statement. The reason for not breaking out of an if statement is because it is commonly used to

I try to use a simple loop, in my real code this loop is more complex, and I need to break this iteration like: {% for post in posts %} {% if post.id == 10 %} {# break #} {% endif %} <h2>{{ post.heading }}</h2> {% endfor %} How can I use behavior of break or continue of PHP control structures in Twig? From docs TWIG docs : Unlike in PHP, it's not possible to break or continue in a loop. But still: You can however filter the sequence during iteration which allows you to skip items. Example 1 (for huge lists you can filter posts using slice , slice(start, length) ): {% for post in posts|slice(0

I'm trying to use a break statement in a for loop, but since I'm also using strict subs in my Perl code, I'm getting an error saying: Bareword "break" not allowed while "strict subs" in use at ./final.pl line 154. Is there a workaround for this (besides disabling strict subs)? My code is formatted as follows: for my $entry (@array){ if ($string eq "text"){ break; } } Zain Rizvi Oh, I found it. You use last instead of break for my $entry (@array){ if ($string eq "text"){ last; } } Kent Fredric Additional data (in case you have more questions): FOO: { for my $i ( @listone ){ for my $j ( @listtwo

The keyword break in Java can be used for breaking out of a loop or switch statement. Is there anything which can be used to break from a method? Use the return keyword to exit from a method. public void someMethod() { //... a bunch of code ... if (someCondition()) { return; } //... otherwise do the following... } From the Java Tutorial that I linked to above: Any method declared void doesn't return a value. It does not need to contain a return statement, but it may do so. In such a case, a return statement can be used to branch out of a control flow block and exit the method and is simply

I have written a program in JAVA language which accepts inputs from console by using Scanner class.... now I want to add this ability to my code to exist a loop (while) when user presses Esc Button. so far I thought Keyboard class can help me but it was just like Scanner...I tried to use events but do not know how to use them correctly.... Source code: package switchCase_v1; import cs1.Keyboard; import java.util.EventObject; import java.awt.AWTEvent; import java.awt.event.KeyEvent; import java.awt.event.ComponentEvent; import java.awt.event.InputEvent; import java.util.*; public class

I have code like the following: function test(obj) { if(//some conditon) { obj.onload(); }else{ obj.onerror(); } } for(var i=0;i<4;i++){ test({ onload:function(e){ //some code to run }, onerror:function(e){ break; } }); } The gist is the test() function is a function to make an XHR request (it is actually an API of the Appcelerator Titanium platform so I have no control over it) and I'm looping something to call the test function. I need to break the loop on the onerror function, but I get an error saying the break is not inside a loop or switch statement. How can I rewrite this? penartur If

I have a homework to implement a simple testing application, below is my current code: import java.util.*; public class Test{ private static int typing; public static void main(String argv[]){ Scanner sc = new Scanner(System.in); System.out.println("Testing starts"); while(sc.hasNextInt()){ typing = sc.nextInt(); switch(typing){ case 0: break; //Here I want to break the while loop case 1: System.out.println("You choosed 1"); break; case 2: System.out.println("You choosed 2"); break; default: System.out.println("No such choice"); } } System.out.println("Test is done"); } } What I want to do now