break

List ForEach break

女生的网名这么多〃 提交于 2019-11-28 07:02:43
问题 is there a way to break out of the foreach extension method? The "break" keyword doesn't recognize the extension method as a valid scope to break from. //Doesn't compile Enumerable.Range(0, 10).ToList().ForEach(i => { System.Windows.MessageBox.Show(i.ToString()); if (i > 2)break; }); Edit: removed "linq" from question note the code is just an example to show break not working in the extension method... really what I want is for the user to be able to abort processing a list.. the UI thread

How to break out of while loop in Python?

非 Y 不嫁゛ 提交于 2019-11-28 06:51:44
I have to make this game for my comp class, and I can't figure out how how break out of this loop. See, I have to play against the "computer," by rolling bigger numbers, and seeing who has the bigger score. But I can't figure out how to "break" from my turn, and transition to the computers turn. I need "Q" (quit) to signal the beginning of the computers turn, but I don't know how to do it. ans=(R) while True: print('Your score is so far '+str(myScore)+'.') print("Would you like to roll or quit?") ans=input("Roll...") if ans=='R': R=random.randint(1, 8) print("You rolled a "+str(R)+".") myScore

How do I break from the main/outer loop in a double/nested loop? [duplicate]

你离开我真会死。 提交于 2019-11-28 06:12:51
This question already has an answer here: How do I break out of nested loops in Java? 33 answers If I have loop in a loop and once an if statement is satisfied I want to break main loop, how am I supposed to do that? This is my code: for (int d = 0; d < amountOfNeighbors; d++) { for (int c = 0; c < myArray.size(); c++) { if (graph.isEdge(listOfNeighbors.get(d), c)) { if (keyFromValue(c).equals(goalWord)) { // Once this is true I want to break main loop. System.out.println("We got to GOAL! It is "+ keyFromValue(c)); break; // This breaks the second loop, not the main one. } } } } Jigar Joshi

Is using labels in JavaScript bad practice?

青春壹個敷衍的年華 提交于 2019-11-28 04:51:41
I just found out about using label s in JavaScript, such as: for (var i in team) { if(i === "something") { break doThis: //Goto the label } else { doThat(); } } doThis: //Label doIt(); I've not heard about this until now and I can't find much information online about it and I'm beginning to think there is a reason for that. It seems to me like this is similar to a GOTO statement in other languages and would be considered bad practice. Would I be right in assuming this? Those are loop breaker identifiers. They are useful if you have nested loops (loops inside loops) and using these identifiers,

Breaking out of an outer loop from an inner loop in javascript

笑着哭i 提交于 2019-11-28 04:36:30
问题 while(valid){ for(loop through associative array){ if(!valid){ break; } } } I have tried to find a way to break out of the while loop from the if statement. So far, the best method seems to be the goto method that is non-existant in Javascript. What is the best way to cause the if statement to break out of both of the loops it is nested in? Thanks in advance for the help! 回答1: Depending on what your conditionals are, it should be easy to set the iterator of your for-loop to something that

Why it is a bad practice to use break/continue labels in OOP (e.g. Java, C#)? [closed]

大兔子大兔子 提交于 2019-11-28 03:25:17
问题 As it currently stands, this question is not a good fit for our Q&A format. We expect answers to be supported by facts, references, or expertise, but this question will likely solicit debate, arguments, polling, or extended discussion. If you feel that this question can be improved and possibly reopened, visit the help center for guidance. Closed 7 years ago . I was told that using break and continue labels in an OOP language is not OOP programming style. Can you explain in detail why and

Break out of a while loop using a function

房东的猫 提交于 2019-11-28 02:14:14
Is there any way to break out of infinite loops using functions? E.g., # Python 3.3.2 yes = 'y', 'Y' no = 'n', 'N' def example(): if egg.startswith(no): break elif egg.startswith(yes): # Nothing here, block may loop again print() while True: egg = input("Do you want to continue? y/n") example() This causes the following error: SyntaxError: 'break' outside loop Please explain why this is happening and how this can be fixed. As far as I'm concerned you cannot call break from within example() but you can make it to return a value( eg : A boolean ) in order to stop the infinite loop The code: yes=

Immediate exit of 'while' loop in C++ [closed]

拟墨画扇 提交于 2019-11-27 23:33:23
问题 How do I exit a while loop immediately without going to the end of the block? For example, while (choice != 99) { cin >> choice; if (choice == 99) //Exit here and don't get additional input cin>>gNum; } Any ideas? 回答1: Use break? while(choice!=99) { cin>>choice; if (choice==99) break; cin>>gNum; } 回答2: cin >> choice; while(choice!=99) { cin>>gNum; cin >> choice } You don't need a break, in that case. 回答3: Use break , as such: while(choice!=99) { cin>>choice; if (choice==99) break; //exit here

How do I allow breaking on 'System.NullReferenceException' in VS2010?

拟墨画扇 提交于 2019-11-27 23:20:35
问题 I have a VS 2010 C# .NET 4 project. The issue is that the program is not breaking on 'NullReferenceException' errors during debugging. The output window will display the following: A first chance exception of type 'System.NullReferenceException' occurred in myProgram.exe ...but the debugger will just exit out of the function and continue running the rest of the program. How do I change this behavior so that the debugger will break on these exceptions? 回答1: Go to Debug -> Exceptions -> Search

Nested jQuery.each() - continue/break

纵饮孤独 提交于 2019-11-27 19:37:01
Consider the following code: var sentences = [ 'Lorem ipsum dolor sit amet, consectetur adipiscing elit.', 'Vivamus aliquet nisl quis velit ornare tempor.', 'Cras sit amet neque ante, eu ultrices est.', 'Integer id lectus id nunc venenatis gravida nec eget dolor.', 'Suspendisse imperdiet turpis ut justo ultricies a aliquet tortor ultrices.' ]; var words = ['ipsum', 'amet', 'elit']; $(sentences).each(function() { var s = this; alert(s); $(words).each(function(i) { if (s.indexOf(this) > -1) { alert('found ' + this); return false; } }); }); The interesting part is the nested jQuery.each() loops.