branch-prediction

Using rdmsr/rdpmc for branch prediction accuracy

孤街浪徒 提交于 2021-01-27 04:21:08
问题 I am trying to understand how does a branch prediction unit work in a CPU. I have used papi and also linux's perf-events but both of them do not give accurate results (for my case). This is my code: void func(int* arr, int sequence_len){ for(int i = 0; i < sequence_len; i++){ // region starts if(arr[i]){ do_sth(); } // region ends } } My array consists of 0's and 1's. It has a pattern with a size of sequence_len . For example, if my size is 8, then it has a pattern of 0 1 0 1 0 0 1 1 or

What happens with nested branches and speculative execution?

放肆的年华 提交于 2021-01-24 07:06:25
问题 Alright, so I know that if a particular conditional branch has a condition that takes time to compute (memory access, for instance), the CPU assumes a condition result and speculatively executes along that path. However, what would happen if, along that path, yet another slow conditional branch pops up (assuming, of course, that the first condition hasn't been resolved yet and the CPU can't just commit the changes)? Does the CPU just speculate inside the speculation? What happens if the last

What happens with nested branches and speculative execution?

女生的网名这么多〃 提交于 2021-01-24 06:59:30
问题 Alright, so I know that if a particular conditional branch has a condition that takes time to compute (memory access, for instance), the CPU assumes a condition result and speculatively executes along that path. However, what would happen if, along that path, yet another slow conditional branch pops up (assuming, of course, that the first condition hasn't been resolved yet and the CPU can't just commit the changes)? Does the CPU just speculate inside the speculation? What happens if the last

What happens with nested branches and speculative execution?

假如想象 提交于 2021-01-24 06:59:08
问题 Alright, so I know that if a particular conditional branch has a condition that takes time to compute (memory access, for instance), the CPU assumes a condition result and speculatively executes along that path. However, what would happen if, along that path, yet another slow conditional branch pops up (assuming, of course, that the first condition hasn't been resolved yet and the CPU can't just commit the changes)? Does the CPU just speculate inside the speculation? What happens if the last

How branch predictor and branch target buffer co-exist?

╄→гoц情女王★ 提交于 2020-12-30 03:51:16
问题 My question is how they co-exist and work together in modern CPU architecture? 回答1: You've got it slightly reversed. On every fetch you index into your branch predictor, which tells you whether the instruction that you have just received will be decoded into a taken branch. If not, you fetch the next sequential address. But if your branch predictor says that it will be a taken branch, you don't know which instruction to fetch next, since you haven't decoded this instruction yet. So in order

How branch predictor and branch target buffer co-exist?

ε祈祈猫儿з 提交于 2020-12-30 03:43:08
问题 My question is how they co-exist and work together in modern CPU architecture? 回答1: You've got it slightly reversed. On every fetch you index into your branch predictor, which tells you whether the instruction that you have just received will be decoded into a taken branch. If not, you fetch the next sequential address. But if your branch predictor says that it will be a taken branch, you don't know which instruction to fetch next, since you haven't decoded this instruction yet. So in order

How branch predictor and branch target buffer co-exist?

╄→гoц情女王★ 提交于 2020-12-30 03:43:01
问题 My question is how they co-exist and work together in modern CPU architecture? 回答1: You've got it slightly reversed. On every fetch you index into your branch predictor, which tells you whether the instruction that you have just received will be decoded into a taken branch. If not, you fetch the next sequential address. But if your branch predictor says that it will be a taken branch, you don't know which instruction to fetch next, since you haven't decoded this instruction yet. So in order

How branch predictor and branch target buffer co-exist?

两盒软妹~` 提交于 2020-12-30 03:42:07
问题 My question is how they co-exist and work together in modern CPU architecture? 回答1: You've got it slightly reversed. On every fetch you index into your branch predictor, which tells you whether the instruction that you have just received will be decoded into a taken branch. If not, you fetch the next sequential address. But if your branch predictor says that it will be a taken branch, you don't know which instruction to fetch next, since you haven't decoded this instruction yet. So in order