big-o

问题 My function should return the missing element in a given array range. So i first sorted the array and checked if the difference between i and i+1 is not equal to 1, i'm returning the missing element. // Given an array A such that: // A[0] = 2 // A[1] = 3 // A[2] = 1 // A[3] = 5 // the function should return 4, as it is the missing element. function solution(A) { A.sort((a,b) => { return b<a; }) var len = A.length; var missing; for( var i = 0; i< len; i++){ if( A[i+1] - A[i] >1){ missing = A[i

问题 My function should return the missing element in a given array range. So i first sorted the array and checked if the difference between i and i+1 is not equal to 1, i'm returning the missing element. // Given an array A such that: // A[0] = 2 // A[1] = 3 // A[2] = 1 // A[3] = 5 // the function should return 4, as it is the missing element. function solution(A) { A.sort((a,b) => { return b<a; }) var len = A.length; var missing; for( var i = 0; i< len; i++){ if( A[i+1] - A[i] >1){ missing = A[i

问题 My function should return the missing element in a given array range. So i first sorted the array and checked if the difference between i and i+1 is not equal to 1, i'm returning the missing element. // Given an array A such that: // A[0] = 2 // A[1] = 3 // A[2] = 1 // A[3] = 5 // the function should return 4, as it is the missing element. function solution(A) { A.sort((a,b) => { return b<a; }) var len = A.length; var missing; for( var i = 0; i< len; i++){ if( A[i+1] - A[i] >1){ missing = A[i

问题 This question already has answers here : T(n) = T(n/10) + T(an) + n, how to solve this? (3 answers) Closed last month . Given: T(n) = T(n/10) + T(an) + n for some a (which I know nothing about its value), and that: T(n) = 1 if n < 10 . I want to check if the following is possible (for some a values, and I want to find the smallest possible a ): For every c > 0 there is n 0 > 0 such that for every n > n 0 , T(n) >= c * n Or in other words T(n)=omega(n) Any help is appreciated. 回答1: Suppose

问题 I was reading about Big-O Notation So, any algorithm that is O(N) is also an O(N^2). It seems confusing to me, I know that Big-O gives upper bound only. But how can an O(N) algorithm also be an O(N^2) algorithm. Is there any examples where it is the case? I can't think of any. Can anyone explain it to me? 回答1: "Upper bound" means the algorithm takes no longer than (i.e. <= ) that long (as the input size tends to infinity, with relevant constant factors considered). It does not mean it will

问题 I was reading about Big-O Notation So, any algorithm that is O(N) is also an O(N^2). It seems confusing to me, I know that Big-O gives upper bound only. But how can an O(N) algorithm also be an O(N^2) algorithm. Is there any examples where it is the case? I can't think of any. Can anyone explain it to me? 回答1: "Upper bound" means the algorithm takes no longer than (i.e. <= ) that long (as the input size tends to infinity, with relevant constant factors considered). It does not mean it will

问题 I have to prepare explanation of time complexity of removing vertex ( O(|V| + |E|) ) and edge ( O(|E|) ) in Adjency List. When removing vertex from graph with V vertices and E edges we need to go through all the edges ( O(|E|) ), of course, to check if which ones need to be removed with the vertex, but why do we need to check all vertices ? I don't understand why in order to remove edge we need to go through all the edges. I think I might have bad understanding from the beginning, so would

问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 2 months ago . Improve this question Is there a programmatic way or eclipse plugin to calculate big-O notation for java method ? 回答1: No, there isn't such plugin, and if it was, it would be a mere approximation. Namely, even determining whether the program will finish running or not is

问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 2 months ago . Improve this question Is there a programmatic way or eclipse plugin to calculate big-O notation for java method ? 回答1: No, there isn't such plugin, and if it was, it would be a mere approximation. Namely, even determining whether the program will finish running or not is

来源： https://stackoverflow.com/questions/56194189/is-omn-the-same-as-omaxm-n