assertion

Compile-time assertion to determine if pointer is an array

白昼怎懂夜的黑 提交于 2021-02-19 03:12:55
问题 Currently, I have the following block of code to make safe string copying (it works): #define STRCPY(dst, src) do { assert(((void*)(dst)) == ((void*) & (dst))); \ strlcpy(dst, src, sizeof(dst)); } while (0) So it accepts the construction like: const char *src = "hello"; char dest[5]; STRCPY(dest, src); //hell And denies the following: void (char *dst) { STRCPY(dst, "heaven"); //unknown size of dst } The problem is that the block of code creates an assertion. Is there a way to perform this

Compile-time assertion to determine if pointer is an array

半世苍凉 提交于 2021-02-19 03:12:00
问题 Currently, I have the following block of code to make safe string copying (it works): #define STRCPY(dst, src) do { assert(((void*)(dst)) == ((void*) & (dst))); \ strlcpy(dst, src, sizeof(dst)); } while (0) So it accepts the construction like: const char *src = "hello"; char dest[5]; STRCPY(dest, src); //hell And denies the following: void (char *dst) { STRCPY(dst, "heaven"); //unknown size of dst } The problem is that the block of code creates an assertion. Is there a way to perform this

What does overflowing mean in this case?

随声附和 提交于 2021-01-27 19:40:26
问题 I have found an algorithm to multiply in modoulus. The next pseudocode is taken from wikipedia, page Modular exponention, section Right-to-left binary method. The full pseudocode is function modular_pow(base, exponent, modulus) Assert :: (modulus - 1) * (modulus - 1) does not overflow base result := 1 base := base mod modulus while exponent > 0 if (exponent mod 2 == 1): result := (result * base) mod modulus exponent := exponent >> 1 base := (base * base) mod modulus return result I don't

'CityListViewSet' should either include a `serializer_class` attribute, or override the `get_serializer_class()` method

我与影子孤独终老i 提交于 2021-01-27 04:29:06
问题 I am assuming by the error in the title, once more here for clarity 'CityListViewSet' should either include a `serializer_class` attribute, or override the `get_serializer_class()` method. that my serializer isn't connected to my view, which in my code it should be. I'm not really sure where the bug is in this one. I wonder if any of you have seen something similar? Here is the code. Router: router.register(r'city-list', CityListViewSet, base_name='city-list') view: class CityListViewSet

Why do we use assert() and assert_options() in PHP?

拥有回忆 提交于 2021-01-20 18:13:31
问题 I am new to using PHP and am learning it by reading the documentation on php.net - currently the page for assert() to know about those assert() and assert_options() functions, but it does not explain why we use them and what these functions do in simple words. What do these functions and why do we use them in PHP? 回答1: Assert() is a clever function that works along the same lines as our print statements, but they only have any effect if a certain condition is not matched. Essentially, assert(

Why do we use assert() and assert_options() in PHP?

十年热恋 提交于 2021-01-20 18:13:22
问题 I am new to using PHP and am learning it by reading the documentation on php.net - currently the page for assert() to know about those assert() and assert_options() functions, but it does not explain why we use them and what these functions do in simple words. What do these functions and why do we use them in PHP? 回答1: Assert() is a clever function that works along the same lines as our print statements, but they only have any effect if a certain condition is not matched. Essentially, assert(

How to enable assertions?

痴心易碎 提交于 2020-12-25 09:46:56
问题 In my online Java programming class I have to write a program where the user enters their age, and checks if it's between 0 and 125 - if it isn't, it shows an error code, and I need to use assertions to do that. Here is my code: import java.util.Scanner; public class eproject1 { public static void main(String args[]) { Scanner input = new Scanner(System.in); System.out.print("What is your age? "); int num = input.nextInt(); System.out.println(num); assert(num >= 1 && num < 125); System.out

Is actively throwing AssertionError in Java good practice? [duplicate]

天涯浪子 提交于 2020-06-24 04:31:33
问题 This question already has answers here : What is an AssertionError? In which case should I throw it from my own code? (5 answers) Closed 3 years ago . Looking through Joshua Bloch's 'Effective Java - Second Edition', I stumbled upon the following code on page 152: double apply(double x, double y) { switch(this) { case PLUS: return x + y; case MINUS: return x - y; case TIMES: return x * y; case DIVIDE: return x / y; } throw new AssertionError("Unknown op: " + this); } Now what confuses me is,

Is actively throwing AssertionError in Java good practice? [duplicate]

偶尔善良 提交于 2020-06-24 04:31:26
问题 This question already has answers here : What is an AssertionError? In which case should I throw it from my own code? (5 answers) Closed 3 years ago . Looking through Joshua Bloch's 'Effective Java - Second Edition', I stumbled upon the following code on page 152: double apply(double x, double y) { switch(this) { case PLUS: return x + y; case MINUS: return x - y; case TIMES: return x * y; case DIVIDE: return x / y; } throw new AssertionError("Unknown op: " + this); } Now what confuses me is,

Is actively throwing AssertionError in Java good practice? [duplicate]

眉间皱痕 提交于 2020-06-24 04:30:57
问题 This question already has answers here : What is an AssertionError? In which case should I throw it from my own code? (5 answers) Closed 3 years ago . Looking through Joshua Bloch's 'Effective Java - Second Edition', I stumbled upon the following code on page 152: double apply(double x, double y) { switch(this) { case PLUS: return x + y; case MINUS: return x - y; case TIMES: return x * y; case DIVIDE: return x / y; } throw new AssertionError("Unknown op: " + this); } Now what confuses me is,