arrays

问题 I would like to count how many times is every string in array and sort them by number of times they exist in array I have this code now hlasy.sort(); var zaciatok = null; var pocet = 0; for (var i = 0; i < hlasy.length; i++) { if (hlasy[i] != zaciatok) { if (pocet > 0) { console.log(zaciatok + ' má ' + pocet + ' hlasov'); } zaciatok = hlasy[i]; pocet = 1; } else { pocet++; } } if (pocet > 0) { console.log(zaciatok + ' má ' + pocet + ' Hlasov'); } it works, but it outputs strings from array

问题 The task is: You will be provided with an initial array (the first argument in the destroyer function), followed by one or more arguments. Remove all elements from the initial array that are of the same value as these arguments. While working through it I found some Array.filter behaviour I'm struggling to understand: function destroyer(arr) { for (var i = 1; i<arguments.length; i++){ toDelete = arguments[i]; arr.filter(isItIn); } return arr; } function isItIn(item, undefined, array){ return

问题 I have a object array looking something like this: [0] = { transportnumber: '45', time: '10:28:00', date:"2017-01-16"} [1] = { transportnumber: '45', time: '10:38:00', date:"2017-01-16"} [2] = { transportnumber: '45', time: '10:48:00', date:"2017-01-16"} [3] = { transportnumber: '14', time: '10:12:00', date:"2017-01-16"} [4] = { transportnumber: '14', time: '10:24:00', date:"2017-01-16"} [5] = { transportnumber: '14', time: '10:52:00', date:"2017-01-16"} The object array will always look like

问题 I have a table with form, surname, lastname, email and a rectangle. I have to insert, in the rectangle, an array with arrays with points of timelines etc. I create a customer with form, surname, lastname and email, add them to indexeddb, load them later to insert the rectangle-array. After that, I want to put the newobjectstore in the indexeddb where the email is the same from my customer I choose/inserted. But with this code my array will be put in a new Objectstore with its own ID. function

问题 When I am creating an array of Example objects, I call something like initializeArray(); I use a simple nested for loop to traverse through the array and then assign new objects with values to each index of the array using exampleArr[i][j] = new Example(false, false, false, 0); however, calling this gives me an java.lang.ArrayIndexOutofBoundsException:0 at the line above. I am assuming that I am instantiating the new object incorrectly, as this also happens in another method which is supposed

问题 Beginner in Java using an old textbook and Head First: Java books to figure some stuff out. I have three arrays all parallel. I need to be able to sort by Title, Author, or Page Count based on user selection. I can sort one using Arrays.sort() but I'm getting hung up on how to sort the other two arrays to correspond to the new sorted one. Say I sort the BookTitle array, but I'm going to need to display the proper author and page count of its respective arrays and I'm stumped. do { entry =

问题 I am reshaping a 1D array into 3D using the following. It works fine but it throws an error when x is 7267. I understand that it is not possible to slice an odd number as an int without losing some values. Would appreciate any solution to this. code x = 7248 y= 24 A = np.arange(x) A.reshape(int(x/y),y,1).transpose() output array([[[ 0, 24, 48, ..., 7176, 7200, 7224], [ 1, 25, 49, ..., 7177, 7201, 7225], [ 2, 26, 50, ..., 7178, 7202, 7226], ..., [ 21, 45, 69, ..., 7197, 7221, 7245], [ 22, 46,

问题 Beginner in Java using an old textbook and Head First: Java books to figure some stuff out. I have three arrays all parallel. I need to be able to sort by Title, Author, or Page Count based on user selection. I can sort one using Arrays.sort() but I'm getting hung up on how to sort the other two arrays to correspond to the new sorted one. Say I sort the BookTitle array, but I'm going to need to display the proper author and page count of its respective arrays and I'm stumped. do { entry =

问题 I want to rank and unrank permutations with one cycle in lexicographical order with a given len. A permutation with one cycles is where you can visit in this cycle each element. p:= (2,3,1) is a permutation with one cycle. Has rank 1. p:= (3,1,2) has 1 cycle too, but rank 2, because the permutation is lexicographical greater the frist so it becomes a greater rank. p:= (1,2,3) is a permutation with 3 cycles. (1),(2),(3) How can I efficently rank (permutation with one cycle to rank) and unrank

问题 Given a multidimensional array like this: var arr = [ "apple", ["banana", "strawberry","dsffsd", "apple"], "banana", ["sdfdsf","apple",["apple",["nonapple", "apple",["apple"]]]] ,"apple"]; the challenge was to write a function that keeps the array and an item as arguments and return how many times that item appears in the array. My first solution did the trick: function countItems(arr, item, sumarr = []) { // sumarr = array to store items matched for (let i = 0; i < arr.length; i++ ){ //