argv

问题 Following this post, where I have found a temporary workaround for my other problem, I want to know if I can replace the int argc, char** argv with a std::vector<std::string> variable/object. Consider the imaginary code: #include <iostream> #include <CloseLibrary> void someFunction(int argc, char** argv){ for (int i = 0; i < argc; ++i) { std::cout << argv[i] << std::endl; } } int myFunc(int argc, char** argv){ someFunction(argc, argv); return 0; } where the CloseLibrary is a closed library

问题 As we know from documentation: -c If this option is given, the first element of sys.argv will be "-c" and the current directory will be added to the start of sys.path (allowing modules in that directory to be imported as top level modules). How can I get full interpreter command line options? I need it to solve this: https://github.com/mitsuhiko/werkzeug/blob/f50bdc04cf1c8d71d12d13a0c8ef2878477f4d24/werkzeug/_reloader.py#L141 If I start werkzeug development server, then it will lost -c cmd

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 12 days ago . To solve my problem here, I want to know if/how I can define the second variable of the command line arguments in a format other than char** argv or char* argv[] . The reason is that pybind11 doesn't allow either of those in the inputs of a function. Here are the methods I have tried: Method 1:

问题 On Solaris I got a pointer to argv[0] with getexecname and then I can memcpy at that location. (per Finding current executable's path without /proc/self/exe) I was wondering how to get a pointer to argv[0] in Linux I did readlink on /proc/self/exe but it doesn't give me a pointer to it. THanks 回答1: &argv[0] gets you a pointer to argv[0] . You can overwrite the characters stored in the array that argv[0] is pointing at, so long as you don't go past the existing null terminator; however it

问题 I have a script "task.sh" with the following content: #!/bin/bash CUR_DIR=`pwd` SCRIPTPATH="${CUR_DIR}/`dirname $0`" when I call it with "bash task.sh" it works as expected but when it is called with ". task.sh" $ . log/task.sh dirname: invalid option -- b Try `dirname --help' for more information. When the script is being scheduled in crontab it is not working as well. Can someone tell me what am I doing wrong or a different way in order to get the directory of a script that is not the

问题 I am trying to launch a legacy application in GDB, and it requires that it's argv[0] value not contain anything other than alphanumeric characters. Whenever I launch the program in GDB it seems that it expands the name to be the full path before running the program, so I get an error like (because it can't deal with the slashes): "Cannot find /home/user/myapp ..." Is it possible to run a program in GDB with a relative path, so that it will just see "myapp"? 回答1: Gdb normally runs target

问题 I am trying to launch a legacy application in GDB, and it requires that it's argv[0] value not contain anything other than alphanumeric characters. Whenever I launch the program in GDB it seems that it expands the name to be the full path before running the program, so I get an error like (because it can't deal with the slashes): "Cannot find /home/user/myapp ..." Is it possible to run a program in GDB with a relative path, so that it will just see "myapp"? 回答1: Gdb normally runs target

问题 I wrote a code below #include<stdio.h> int main(int argc, char *argv[]) { char cmd[50]="dir"; if (argc == 2) { sprintf(cmd,"dir %s",argv[1]); } if (argc == 3) { sprintf(cmd,"dir %s %s", argv[1], argv[2]); } printf("%s\n",cmd); system(cmd); return 0; } when I executed like below I think can't pass '*' by *argv[] How can I pass something like "*.c" ? update code #include<stdio.h> int main(int argc, char *argv[]) { char cmd[50]="dir"; if (argc == 2) { sprintf(cmd,"dir %s",argv[1]); } if (argc ==

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 12 months ago . I've got a project about moving certain files from one directory to another. I have all finished except that the output is kind of strange. I am required to provide the destination path in the argsv array, but when I try to execute my code, it compiles and works but shows the wrong path containing many paths

问题 I have a script that takes sys.argv and the input may contain special characters (semicolon). I just need the input as string, but semicolon messes everything up.. I have: def myscript(text) print text a = myscript(sys.argv[1]) print a I try: >> python script.py "With these words she greeted Prince Vasili Kuragin, a man of high rank and importance, who was the first to arrive at her reception. Anna Pavlovna had had a cough for some days. She was, as she said, suffering" from la grippe; grippe