argc

I noticed that the main.cpp in a Qt application has to contain the following line: QApplication app(argc, argv); I know that argc is the number of command-line arguments, and argv is that array list of command-line arguments. But, the question in my mind is: what are those arguments I'm passing to the constructor and at the same time cannot explicitly see? What is working behind the scences out there? Thanks. There are no hidden arguments. You can explicitly see every argument- argc, argv . There's nothing in that line of code that's behind the scenes. From looking at your comments to other

I'm using Jython from within Java; so I have a Java setup similar to below: String scriptname="com/blah/myscript.py" PythonInterpreter interpreter = new PythonInterpreter(null, new PySystemState()); InputStream is = this.getClass().getClassLoader().getResourceAsStream(scriptname); interpreter.execfile(is); And this will (for instance) run the script below: # myscript.py: import sys if __name__=="__main__": print "hello" print sys.argv How I pass in 'commandline' arguments using this method ? (I want to be able to write my Jython scripts so that I can also run them on the commandline with

I have a working program but now I have to use the int argc and char *argv[] parameters to main . Whenever I try to do this it gives me errors that it cannot save. Is there any way to make argc and argv work in Eclipse? I guess your problem is that you don't know hot to pass argument to you program, when you execute it through eclipse isn't it ? If that is what you want, read the following. Click on the "Project->Properties" then in "Run/Debug settings" click on the "New button". Choose C++ application. Here you can see that there are 4 tabs, and the second tab is called "arguments". In this

I have problem with the number of argc that passed to program so, when i check the argc it's not equal to 2 !! need help, how can i solve that problem ? C code snippet : if (2 != argc) { fprintf(stderr, "Usage: %s <port>\n", argv[0]); exit(1); } Don't forget that the program name itself counts as an arg. myProgram -flag variable is an argc of 3 来源： https://stackoverflow.com/questions/12904222/checking-value-of-argc

I'm using a shared host (fasthostingdirect) and for some reason they have this flag turned off by default. This means I'm unable to access PHP command line parameters... unless I use the -n (= --no-php-info ) flag after php.exe . Have tried ini_set('register_argc_argv', 1) in my php file but it has no effect. Am guessing this is due to the clamped down nature of the hosting provider, however they don't stop the -n option - not sure of the other implications of using this though. Does anyone have any better suggestions? The ini_set('register_argc_argv', 1) does not work because by the time the

Is it possible to execute a process whose argc = 0? I need to execute a program but it is extremely important for its argc to be equal to 0. Is there a way to do that? I tried to put 2^32 arguments in the command line so that it appears as if argc = 0 but there is a maximum limit to the number of arguments. You can write a program that calls exec directly; that allows you to specify the command-line arguments (including the program name) and lack thereof. You may use linux system call execve() . int execve(const char *filename, char *const argv[], char *const envp[]); You may pass the filename