apache-commons-httpclient

How does HttpAsyncClient 4 work?

纵然是瞬间 提交于 2020-08-24 06:58:11
问题 In previous versions of HttpClient target host was set up into client itself. In last version (for HttpAsyncClient it's 4.1.1) host is set up into HttpRequest ( HttpGet , HttpPost etc.) every time I do a request. I want to use persistent connection, so I use HttpAsyncClient . I create and use it like this: CloseableHttpAsyncClient client = HttpAsyncClients.createDefault(); client.start(); List<Future<HttpResponse>> responses = new ArrayList<>(); for (int i = 0; i < 10; i++) { HttpGet get =

How does HttpAsyncClient 4 work?

我的未来我决定 提交于 2020-08-24 06:57:59
问题 In previous versions of HttpClient target host was set up into client itself. In last version (for HttpAsyncClient it's 4.1.1) host is set up into HttpRequest ( HttpGet , HttpPost etc.) every time I do a request. I want to use persistent connection, so I use HttpAsyncClient . I create and use it like this: CloseableHttpAsyncClient client = HttpAsyncClients.createDefault(); client.start(); List<Future<HttpResponse>> responses = new ArrayList<>(); for (int i = 0; i < 10; i++) { HttpGet get =

Angular 6 set withCredentials to true with every HttpClient call

徘徊边缘 提交于 2020-02-27 03:31:25
问题 If you want the credentials (cookie authentication token) to be passable through a call, you need to add { withCredentials: true } in your httpclient call. Something like this: import { HttpClient } from '@angular/common/http'; ... constructor(private httpclient: HttpClient) { } this.httpclient.get(url, { withCredentials: true }) I would just like to know if there is a way to preset { withCredentials: true } with every single call. I don't want to have to add { withCredentials: true } every

How do I get the Auth Code from the redirect url? OAuth2

大兔子大兔子 提交于 2020-02-25 04:17:35
问题 I'm trying to authenticate my app with an API using OAuth2.0. I'm new to OAuth and only have a basic understanding of it. I have implemented a way to get the access token and make the requests I want, however my method seems a bit inefficient. It could also be my slight lack of knowledge with http requests in Java. Just as a note, i am using the apache http client. Currently what im doing to get authorized is I open the user authorization page directly in the browser with: Desktop.getDesktop(

How do I get the Auth Code from the redirect url? OAuth2

痞子三分冷 提交于 2020-02-25 04:16:08
问题 I'm trying to authenticate my app with an API using OAuth2.0. I'm new to OAuth and only have a basic understanding of it. I have implemented a way to get the access token and make the requests I want, however my method seems a bit inefficient. It could also be my slight lack of knowledge with http requests in Java. Just as a note, i am using the apache http client. Currently what im doing to get authorized is I open the user authorization page directly in the browser with: Desktop.getDesktop(

org.apache.http.entity.FileEntity is deprecated in Android 6 (Marshmallow)

坚强是说给别人听的谎言 提交于 2020-01-16 07:04:16
问题 I'm upgrading an app to API 23 where org.apache.http is deprecated. My current (deprecated) code looks like this: HttpClient httpClient = new DefaultHttpClient(); File file = new File(attr.Value); String url = server_url; HttpPost request = new HttpPost(url); FileEntity fileEntity = new FileEntity(file, "image/png"); request.setEntity(fileEntity); HttpResponse response = httpClient.execute(request); String output = getContent(response.getEntity().getContent()); I've found some suggestions to

Bypass DNS lookup and submit URL to proxy

我只是一个虾纸丫 提交于 2020-01-05 10:17:23
问题 I have Java application that uses Apache HttpComponents to make web request. I have configured the application to use Proxy Servers using the JVM Property java -Dhttp.proxyHost=127.0.0.1 -Dhttp.proxyPort=3132 Currently my java application client makes DNS lookup in which it will fail. I want the Proxy to do the DNS resolution just like how web browsers do in automatic Proxy configuration mode (with .pac files). 回答1: Try looking here: http://hc.apache.org/httpcomponents-client-ga/httpclient

call Google auth API using Apache HttpClient

最后都变了- 提交于 2020-01-05 04:36:09
问题 I would like to know if it is possible to call a Google API that requires auth such as the Google Calendar API using the Apache HttpClient, and no Google code or libraries. (and need the code to do it) This is the code I have so far, its gets an auth error, What do you use for the user/password? HttpPost request = new HttpPost("https://www.googleapis.com/calendar/v3/users/me/calendarList/primary?key=mykey"); DefaultHttpClient client = new DefaultHttpClient(); client.getCredentialsProvider()

How to submit a post request to a form?

别来无恙 提交于 2020-01-05 04:27:13
问题 Here is the test form Let's say i need to submit first name x and last name y . So , I can submit the get request simply by entering the following url http://www.w3schools.com/tags/demo_form_method.asp?fname=x&lname=y Now, if I change method="post" then the above method does not work. How can I submit the post request programatically and then print the resulting page to console ? I tried to use many methods . For example PostMethod post = new PostMethod("http://www.w3schools.com/tags/demo

commons http client - kerberos token while negotiating has \r\n (carriage return line feed) characters

不羁岁月 提交于 2020-01-04 11:09:18
问题 I am trying to use jakarta commons http client. Doing kerberos authentication to communicate with a server. Authentication always fails. On digging deeper I found out that the kerberos token header has carriage return line feed characters in it which is the root cause of the issue. Why does it have \r\n characters and why is that an issue? 回答1: \r\n characters in the kerberos token is an issue because \r is an HTTP control characters. That essentially means that the server only sees first