ansi-c

ANSI C equivalent of try/catch?

…衆ロ難τιáo~ 提交于 2019-11-28 20:22:35
I have some C code I'm working with, and I'm finding errors when the code is running but have little info about how to do a proper try/catch (as in C# or C++). For instance in C++ I'd just do: try{ //some stuff } catch(...) { //handle error } but in ANSI C I'm a bit lost. I tried some online searches but I don't see enough info about how to make it happen / figured I'd ask here in case anyone can point me in the right direction. Here's the code I'm working with (fairly simple, recursive method) and would like to wrap with try/catch (or equivalent error-handling structure). However my main

How is the size of a variable length array computed at runtime in C99?

浪尽此生 提交于 2019-11-28 00:10:34
问题 In C89, the length of an array is known at compile time. But in C99, with variable length arrays, the length of an array may be unknown before runtime. So how does it get computed? And why couldn't the length of a dynamically allocated array be computed in the same way? 回答1: From ISO/IEC 9899:TC3 Section 6.7.5.2: Array declarators An ordinary identifier (as defined in 6.2.3) that has a variably modified type shall have either block scope and no linkage or function prototype scope. If an

Who defines C operator precedence and associativity?

為{幸葍}努か 提交于 2019-11-27 19:22:08
Introduction In every textbook on C/C++, you'll find an operator precedence and associativity table such as the following: http://en.cppreference.com/w/cpp/language/operator_precedence One of the questions on StackOverflow asked something like this: What order do the following functions execute: f1() * f2() + f3(); f1() + f2() * f3(); Referring to the previous chart I confidently replied that functions have left-to-right associativity so in the previous statements the are evaluated like this in both cases: f1() -> f2() -> f3() After the functions are evaluated you finish the evaluation like

What does static mean in ANSI-C [duplicate]

吃可爱长大的小学妹 提交于 2019-11-27 07:47:46
Possible Duplicate: What does “static” mean in a C program? What does the static keyword mean in C ? I'm using ANSI-C. I've seen in several code examples, they use the static keyword in front of variables and in front of functions. What is the purpose in case of using with a variable? And what is the purpose in case of using with a function? Roux hass Just as a brief answer, there are two usages for the static keyword when defining variables: 1- Variables defined in the file scope with static keyword, i.e. defined outside functions will be visible only within that file. Any attempt to access

String termination - char c=0 vs char c='\\0'

对着背影说爱祢 提交于 2019-11-27 07:04:06
When terminating a string, it seems to me that logically char c=0 is equivalent to char c='\0' , since the "null" (ASCII 0) byte is 0 , but usually people tend to do '\0' instead. Is this purely out of preference or should it be a better "practice"? What is the preferred choice? EDIT: K&R says : "The character constant '\0' represents the character with value zero, the null character. '\0' is often written instead of 0 to emphasize the character nature of some expression, but the numeric value is just 0 . http://en.wikipedia.org/wiki/Ascii#ASCII_control_code_chart Binary Oct Dec Hex Abbr

Why doesn't ANSI C have namespaces?

▼魔方 西西 提交于 2019-11-26 23:31:34
Having namespaces seems like no-brainer for most languages. But as far as I can tell, ANSI C doesn't support it. Why not? Any plans to include it in a future standard? C does have namespaces. One for structure tags, and one for other types. Consider the following definition: struct foo { int a; }; typedef struct bar { int a; } foo; The first one has tag foo, and the later is made into type foo with a typedef. Still no name-clashing happens. This is because structure tags and types (built-in types and typedef'ed types) live in separate namespaces. What C doesn't allow is to create new namespace

Difference between char* var; and char *var;? [duplicate]

杀马特。学长 韩版系。学妹 提交于 2019-11-26 20:26:39
This question already has an answer here: Why is the asterisk before the variable name, rather than after the type? 13 answers Just wondering if there's any difference between: char* var; char *var; or is it just a matter of preference (spacing)? There is no difference in this case. However, you should prefer char *var; . This is because the * is associated more closely with the variable name and is not part of the base type . For example, if you do this: char* a, b; What you have is a , a pointer-to- char , and b , a char . This is confusing! Since the * character is closer to the char

What does static mean in ANSI-C [duplicate]

筅森魡賤 提交于 2019-11-26 13:49:29
问题 This question already has answers here : Closed 8 years ago . Possible Duplicate: What does “static” mean in a C program? What does the static keyword mean in C ? I'm using ANSI-C. I've seen in several code examples, they use the static keyword in front of variables and in front of functions. What is the purpose in case of using with a variable? And what is the purpose in case of using with a function? 回答1: Just as a brief answer, there are two usages for the static keyword when defining

String termination - char c=0 vs char c='\0'

二次信任 提交于 2019-11-26 13:02:37
问题 When terminating a string, it seems to me that logically char c=0 is equivalent to char c=\'\\0\' , since the \"null\" (ASCII 0) byte is 0 , but usually people tend to do \'\\0\' instead. Is this purely out of preference or should it be a better \"practice\"? What is the preferred choice? EDIT: K&R says : \"The character constant \'\\0\' represents the character with value zero, the null character. \'\\0\' is often written instead of 0 to emphasize the character nature of some expression, but

Difference between char* var; and char *var;? [duplicate]

徘徊边缘 提交于 2019-11-26 09:01:49
问题 This question already has answers here : Why is the asterisk before the variable name, rather than after the type? (13 answers) Closed 4 years ago . Just wondering if there\'s any difference between: char* var; char *var; or is it just a matter of preference (spacing)? 回答1: There is no difference in this case. However, you should prefer char *var; . This is because the * is associated more closely with the variable name and is not part of the base type . For example, if you do this: char* a,