anagram

A word is an anagram if the letters in that word can be re-arranged to form a different word. Task: The shortest source code by character count to find all sets of anagrams given a word list. Spaces and new lines should be counted as characters Use the code ruler ---------10--------20--------30--------40--------50--------60--------70--------80--------90--------100-------110-------120 Input: a list of words from stdin with each word separated by a new line. e.g. A A's AOL AOL's Aachen Aachen's Aaliyah Aaliyah's Aaron Aaron's Abbas Abbasid Abbasid's Output: All sets of anagrams, with each set

I am supposed to write a program in JavaScript to find all the anagrams within a series of words provided. e.g.: "monk, konm, nkom, bbc, cbb, dell, ledl, llde" The output should be categorised into rows: 1. monk konm, nkom; 2. bbc cbb; 3. dell ledl, llde; I already sorted them into alphabetical order i.e.: "kmno kmno bbc bbc dell dell" and put them into an array. However I am stuck in comparing and finding the matching anagram within the array. Any help will be greatly appreciated. Javascript objects are excellent for this purpose, since they are essentially key/value stores: // Words to match

I am currently working on a small anagram program that takes all possible permutations of a word and compare them with a dictionary. However, I am unable to get the results to print. The culprit appears to be the == operator, if I put ''.join(words[i]) == compare[j] nothing prints, however, if I input hi and run the program with ''.join(words[i]) == "hi" the entire dictionary prints, but if I invert it to "hi" == compare[j] nothing prints. Thanks in advance for any help! import itertools run = input("Please enter a word: ") dictionary = "dictionary.txt" #input("Please enter the name of the

I'm trying to write a program that checks whether 2 inputs are anagrams. I feel like this should be relatively easy but I can't seem to figure it out. I'm supposed to define a function as: def isAnagram(s1, s2): so far, I have this: word1 = input("Enter a string: ") word2 = input("Enter a second string: ") def isAnagram(s1, s2): s1 = word1.sort() s2 = word2.sort() if s1 == s2: print("This is an anagram") else: print("This is not an anagram) isAnagram() I guess I don't fully understand defining functions, so if you could please explain what's happening, that would be great! You've defined the

input: ['abc', 'cab', 'cafe', 'face', 'goo'] output: [['abc', 'cab'], ['cafe', 'face'], ['goo']] The problem is simple: it groups by anagrams . The order doesn't matter. Of course, I can do this by C++ (that's my mother tongue). But, I'm wondering this can be done in a single line by Python . EDITED: If it's not possible, maybe 2 or 3 lines. I'm a newbie in Python. To check whether two strings are anagram, I used sorting. >>> input = ['abc', 'cab', 'cafe', 'face', 'goo'] >>> input2 = [''.join(sorted(x)) for x in input] >>> input2 ['abc', 'abc', 'acef', 'acef', 'goo'] I think it may be doable

I would like to generate anagram output of a given string without the help of any external libraries such as Google anagram algorithms helper. Example: Input string = "GOD" Output list should look like the following one: G O D GO GD OD OG DG DO GOD GDO ODG OGD DGO DOG That taks turned to be awesome on so many levels. I present you a pure LINQ (but not very efficient) solution. static class Program { static void Main(string[] args) { var res = "cat".Anagrams(); foreach (var anagram in res) Console.WriteLine(anagram.MergeToStr()); } static IEnumerable<IEnumerable<T>> Anagrams<T>(this IEnumerable

I have a method here that takes an array of strings and groups the ones that are anagrams of each other together, with each group forming a sub-array of the main anagram_groups array. The output is fine but I feel like my code is probably overly-complicated. How could my logic and/or syntax be simplified, short of refactoring things into more methods? def combine_anagrams(words) anagram_groups = [] # For each word in array argument words.each do |word| # Tracking variable for the word word_added = false anagram_groups.each do |group| # Check if word already exists (prevents duplicates) if

I'm Making a an ios application where you input 9 lettes and it will output anagrams of those 9 letters. It is like the target word, or 9 letter word in the paper. Like this link: http://nineletterword.tompaton.com/ It doesn't just provide anagrams for 9 letters, it will do it for 4 letters, 5 letters, 6 letters... all of which contain at least the middle letter. I want to make it an offline application, so I don't want to reference any websites or use an online json... How would I go about checking if an array of the 9 letters can be rearranged into a word which is in an English dictionary