2048

开源游戏“2048”IOS移植版

寵の児 提交于 2020-01-10 11:07:47
【推荐】2019 Java 开发者跳槽指南.pdf(吐血整理) >>> 简介 这个游戏是我在今年课余时闲着无聊做的一个益智类小游戏,总共花了4个工作日才完成,为了游戏的效率,做了很多优化,目前在IE5以上浏览器 能够流畅运行,运行时如果屏幕分辨率不兼容,你可以缩放到最佳显示效果。大家可以学习学习,有不足的地方你们可以自己改改,该款游戏是模仿最火爆的游戏“2048 ”的风格 。 授权 本软件使用的是“ GPL ”开源协议。 截图 代码说明 这个游戏是基于HTML4开发的,所以兼容性也挺不错的,电脑配置一般的就可以流畅玩耍了。 代码预览地址 2048 代码下载地址 2048 、 码云 、 Github 2048 - 朝代版 联系方式 QQ:1101587171 或 975738768 备注 1.点击W、S、A、D或上、下、左、右键或鼠标手势(按住并按方向拖动释放)即可玩耍游戏。 2.代码的具体内容,你可以下载并查看。 来源: oschina 链接: https://my.oschina.net/u/207042/blog/268688

What is the optimal algorithm for the game 2048?

纵然是瞬间 提交于 2019-11-26 12:33:35
I have recently stumbled upon the game 2048 . You merge similar tiles by moving them in any of the four directions to make "bigger" tiles. After each move, a new tile appears at random empty position with a value of either 2 or 4 . The game terminates when all the boxes are filled and there are no moves that can merge tiles, or you create a tile with a value of 2048 . One, I need to follow a well-defined strategy to reach the goal. So, I thought of writing a program for it. My current algorithm: while (!game_over) { for each possible move: count_no_of_merges_for_2-tiles and 4-tiles choose the

What is the optimal algorithm for the game 2048?

二次信任 提交于 2019-11-26 02:59:19
问题 I have recently stumbled upon the game 2048. You merge similar tiles by moving them in any of the four directions to make \"bigger\" tiles. After each move, a new tile appears at random empty position with a value of either 2 or 4 . The game terminates when all the boxes are filled and there are no moves that can merge tiles, or you create a tile with a value of 2048 . One, I need to follow a well-defined strategy to reach the goal. So, I thought of writing a program for it. My current

Python: Justifying NumPy array

萝らか妹 提交于 2019-11-25 22:41:55
问题 Please I am a bit new to Python and it has been nice, I could comment that python is very sexy till I needed to shift content of a 4x4 matrix which I want to use in building a 2048 game demo of the game is here I have this function def cover_left(matrix): new=[[0,0,0,0],[0,0,0,0],[0,0,0,0],[0,0,0,0]] for i in range(4): count=0 for j in range(4): if mat[i][j]!=0: new[i][count]=mat[i][j] count+=1 return new This is what this function does if you call it like this cover_left([ [1,0,2,0], [3,0,4