How to define a private property when implementing an interface in Typescript?

Question

I\'m using TypeScript in my project and I have come across an issue. I\'m defining an interface like this:

interface IModuleMenuItem {
    name: string;
}


        

Answer 1

I think you may do it like this

interface IModuleMenuItem{
    name: string
}

class ModuleMenuItem implements IModuleMenuItem {
    private _name: string;
    constructor() {
    _name = "name";
    }

    get name(){
    // your implementation to expose name
    }

    set name(value){
    // your implementation to set name         
    }
 }

Answer 2

In case of having private fields in class, you need to introduce setter and get methods for that field like so:

export class Model {
    private _field: number;

    get field(): number {
        return this._field;
    }

    set field(value: number) {
        this._field= value;
    }
}

And then create the interface as usual (We can not use private modifier for interface fields) like so:

export interface IModel {
 field: number;
}

Then implement it to our class like so:

export class Model implements IModel {
...
}

TypeScript will understand that this model is implemented correctly the interface as we have introduced set and get method.

Answer 3

Use abstract classes instead.

Composition over inheritance.

interface AppInterface {
   app: express.Application
   port: string | number
}

abstract class AbstractApp implements AppInterface {
    app: express.Application
    port: string | number
    constructor(){
        this.app=express()
        this.port=8080
    }
    
    protected defaultMiddlewares(): void {}
}     

class App extends AbstractApp {
    constructor() {
        super()
    }

    protected defaultMiddlewares(): void {
        this.app.use(express.json())
    }
}

Answer 4

Interfaces define "public" contracts and as such it doesn't make sense to have protected or private access modifier on interfaces, which are more of a, let's call it, implementation detail. As such you can't do what you want with an interface.

If you are want to make the property read-only to consumers, but overridable in a subclass then you can do something like this:

interface IModuleMenuItem {
     getName(): string;
}

class ModuleMenuItem implements IModuleMenuItem {
    private name;

    public getName() {
        return name;    
    }

    protected setName(newName : string) {
        name = newName;
    }
}

I think in TypeScript 2.0 (not out yet) you will be able to use the readonly access modifier if you were after initialization-time readonly field - https://basarat.gitbooks.io/typescript/content/docs/types/readonly.html

interface IModuleMenuItem {
     readonly name : string;
}

class ModuleMenuItem implements IModuleMenuItem {
    public readonly name : string;

    constructor() {
        name = "name";
    }
}

Answer 5

The only way you can have an inner state and assign interface to that instead of class and make that state private

class A{
  private state:IA = ...
}