How to dismiss an AlertDialog on a FlatButton click?

Question

I have the following AlertDialog.

showDialog(
            context: context,
            child: new AlertDialog(
              title: const Text(\"Lo         


        

Answer 1

Navigator.of(context, rootNavigator: true).pop('dialog')

worked with me.

Answer 2

If you don't want to return any result, use either of them:

Navigator.of(context).pop();
Navigator.pop(context);

---

But if you do want to return some result, see this

Example:

showDialog(
    context: context,
    builder: (_) {
      return AlertDialog(
        title: Text('Wanna Exit?'),
        actions: [
          FlatButton(
            onPressed: () => Navigator.pop(context, false), // passing false
            child: Text('No'),
          ),
          FlatButton(
            onPressed: () => Navigator.pop(context, true), // passing true
            child: Text('Yes'),
          ),
        ],
      );
    }).then((exit) {
  if (exit == null) return;

  if (exit) {
    // user pressed Yes button
  } else {
    // user pressed No button
  }
});

Answer 3

Navigator.pop(_)

worked for me, but the Flutter Team's gallery contains an example using:

Navigator.of(context, rootNavigator: true).pop()

which also works, and I am tempted to follow their lead.

Answer 4

Navigator.pop() should do the trick. You can also use that to return the result of the dialog (if it presented the user with choices)

Answer 5

pass it in the showDialog barrierDismissible : true

Answer 6

Generally Navigator.pop(context); works.

But If the application has multiple Navigator objects and dialogBox doesn't close, then try this

Navigator.of(context, rootNavigator: true).pop();

If you want to pass result call, try

Navigator.pop(context,result);

OR

Navigator.of(context, rootNavigator: true).pop(result)