Using .filter to compare two arrays and return values that aren't matched

Question

I\'m having some issues comparing the elements of two arrays and filtering out matching values. I only want to return array elements that are NOT included within wordsToRe

Answer 1

use filter and includes to perform this

var fullWordList = ['1','2','3','4','5'];
var wordsToRemove = ['1','2','3'];

var newList = fullWordList.filter(function(word){
   return !wordsToRemove.includes(word);
})
console.log(newList);

Answer 2

That is pretty easy to do using Array.prototype.filter:

var fullWordList = ['1','2','3','4','5'];
var wordsToRemove = ['1','2','3'];

var filteredKeywords = fullWordList.filter(
  word=>!wordsToRemove.includes(word)
//or
//word=>wordsToRemove.indexOf(word)<0
);

Answer 3

forEach on fullWordList is not required, use filter on fullWordList and indexOf() in your function in filter() to check if a number exists in wordsToRemove or not.

var fullWordList = ['1','2','3','4','5'];
var wordsToRemove = ['1','2','3'];

var newList = fullWordList.filter(function(x){
   return wordsToRemove.indexOf(x) < 0;
})
console.log(newList);

Answer 4

Perhaps you could try

var fullWordList = ['1','2','3','4','5'];
var wordsToRemove = ['1','2','3'];
var match = [];

for(let word of fullWordList){
    if(!wordsToRemove.find((val) => val == word))match.push(word);
}

Answer 5

You can use filter and includes to achieve this:

var fullWordList = ['1','2','3','4','5'];
var wordsToRemove = ['1','2','3'];

var filteredKeywords = fullWordList.filter((word) => !wordsToRemove.includes(word));

console.log(filteredKeywords);