How to open app links in flutter webview?

Question

In Flutter, I use the flutter webview plugin to launch a url like:

flutterWebviewPlugin.launch(url)

or

WebviewScaffold(
  url:          


        

Answer 1

You can use webview_flutter in pub.dev Packages

WebView(
        initialUrl: 'https://my.url.com',
        javascriptMode: JavascriptMode.unrestricted,
        navigationDelegate: (NavigationRequest request)
        {
          if (request.url.startsWith('https://my.redirect.url.com'))
          {
            print('blocking navigation to $request}');
            _launchURL('https://my.redirect.url.com');
            return NavigationDecision.prevent;
          }

          print('allowing navigation to $request');
          return NavigationDecision.navigate;
        },
      )

And you can launch url with url_launcher in pub.dev Packages

_launchURL(String url) async {
if (await canLaunch(url)) {
  await launch(url);
} else {
  throw 'Could not launch $url';
}}

Answer 2

You can use web plugin like

 @override
 Widget build(BuildContext context) {
   String url = widget.url;
   return Scaffold(
    body: Center(
    child : WebviewScaffold(
      url: "https://google.com",
      appBar: new AppBar(
        title: new Text(widget.title),
      ),
      withZoom: true,
      withLocalStorage: true,
     )
   ),
 );
}

Answer 3

Looks like you can achieve what you need using this plugin : https://pub.dartlang.org/packages/flutter_web_view

Listen for your redirects:

  flutterWebView.listenForRedirect("fb://profile", true);

Get the value using :

flutterWebView.onRedirect.listen((url) {
   flutterWebView.dismiss();
    //now you have the url
 });

After you have the url you can use this package https://pub.dartlang.org/packages/url_launcher