Django model with FileField — dynamic 'upload_to' argument

Question

I am using the model with FileField to deal with file uploading. Now the files can be uploaded successfully. However, there is one more small improvement I want to make, which i

Answer 1

Instead of a string try passing a function:

def generate_filename(self, filename):
    url = "files/users/%s/%s" % (self.user.username, filename)
    return url

class UserFiles(models.Model):
    user = models.OneToOneField(User)
    file = models.FileField(upload_to=generate_filename)