Units of measurement in C++

Question

I\'m working on a game engine, and currently I\'m stuck designing the IO system. I\'ve made it so, the engine itself doesn\'t handle any file formats, but rathe

Answer 1

You can use the factory design pattern to accomplish what you're looking for. You can create a frequency class with a private constructor and several static methods that will construct the object depending on the units the user wants to use. By keeping the constructor private, the user is forced to declare his units explicitly, which reduces the likelihood of user error.

#include <iostream>

using namespace std;

class frequency
{
public:
  static frequency hertz(int hz)
  {
    return frequency(hz);
  }

  static frequency kilohertz(double kHz)
  {
    return frequency(kHz * KHZ_TO_HZ);
  }

  static frequency rpm(int rpm)
  {
    return frequency(rpm * RPM_TO_HZ);
  }

  int hz()
  {
    return m_hz;
  }

private:
  static const int KHZ_TO_HZ = 1000;
  static const int RPM_TO_HZ = 60;

  frequency(int hz) : m_hz(hz)
  {
  }

  int m_hz;
};

int main()
{
  wcout << frequency::hertz(44100).hz() << "Hz" << endl;
  wcout << frequency::kilohertz(44.100).hz() << "Hz" << endl;
}

Answer 2

I know you mentioned you aren't using C++11 but others looking at this question may be, so here's the C++11 solution using user defined literals:

http://ideone.com/UzeafE

#include <iostream>
using namespace std;

class Frequency
{
public:
    void Print() const { cout << hertz << "Hz\n"; }

    explicit constexpr Frequency(unsigned int h) : hertz(h) {}
private:
    unsigned int hertz;
};
constexpr Frequency operator"" _Hz(unsigned long long hz)
{
    return Frequency{hz};
}
constexpr Frequency operator"" _kHz(long double khz)
{
    return Frequency{khz * 1000};
}

int main()
{
    Frequency(44100_Hz).Print();
    Frequency(44.1_kHz).Print();
    return 0;
}

Output:

44100Hz
44100Hz

Answer 3

The Boost "Units" library is great for this type of thing.

http://www.boost.org/doc/libs/1_55_0/doc/html/boost_units.html