json_decode() expects parameter 1 to be string, array given

Question

What causes this error in my code?

$query = $this->db->query(\"SELECT * FROM tour_foreign ORDER BY id desc\");
        $data = array();
        foreach ($q         


        

Answer 1

here is the solution for similar problem which i was facing while extracting name from user profile facebook json object

$uname=json_encode($userprof);
$uname=json_decode($uname);
echo "Welcome " . $uname -> name  ;

Answer 2

• Make an object

  $obj = json_decode(json_encode($need_to_json));

• Show data from this $obj

  $obj->{'needed'};

Reference

Answer 3

json_decode() is used to decode a json string to an array/data object. json_encode() creates a json string from an array or data. You are using the wrong function my friend, try json_encode();

Answer 4

I think you want json_encode, not json_decode.

Answer 5

Set decoding to true

Your decoding is not set to true. If you don't have access to set the source to true. The code below will fix it for you.

$WorkingArray = json_decode(json_encode($data),true);

Answer 6

Ok I was running into the same issue. What I failed to notice is that I was using json_decode() instead of using json_encode() so for those who are going to come here please make sure you are using the right function, which is json_encode()

Note: Depends on what you are working on but make sure you are using the right function.