Round to the nearest 500, Python

Question

I\'m looking to find a way to round up to the nearest 500.I\'ve been using:

math.ceil(round(8334.00256 + 250, -3))

Whereby I have a value from

Answer 1

Scale, round, unscale:

round(x / 500.0) * 500.0

Edit: To round up to the next multiple of 500, use the same logic with math.ceil() instead of round():

math.ceil(x / 500.0) * 500.0

Answer 2

I personally find rounding a but messy. I'd rather use:

(x+250)//500*500

// means integer division.

EDIT: Oh, I missed that you round "up". Then maybe

-(-x//500)*500

Answer 3

Maybe something like this:

round(float(x) / 500) * 500

The "float" conversion is unnecessary if you are using Python 3 or later, or if you run the statement from __future__ import division for sane integer division.