I have the following scenario:
URL u1 = new URL(\"http://www.yahoo.com/\");
URL u2 = new URL(\"http://www.yahoo.com\");
if (u1.equals(u2)) {
System.out.prin
You can always compare relative URLs with Path.equals-method
ex.
Paths.get("/user/login").equals(Paths.get("/user/login/")))
produce true
You can also use startsWith/endsWith-methods
From the 2007 JavaOne :
The second puzzle, aptly titled "More Joys of Sets" has the user create HashMap keys that consist or several URL objects. Again, most of the audience was unable to guess the correct answer.
The important thing the audience learned here is that the URL object's equals() method is, in effect, broken. In this case, two URL objects are equal if they resolve to the same IP address and port, not just if they have equal strings. However, Bloch and Pugh point out an even more severe Achilles' Heel: the equality behavior differs depending on if you're connected to the network, where virtual addresses can resolve to the same host, or if you're not on the net, where the resolve is a blocking operation. So, as far as lessons learned, they recommend:
Don't use URL; use URI instead. URI makes no attempt to compare addresses or ports. In addition, don't use URL as a Set element or a Map key.
For API designers, the equals() method should not depend on the environment. For example, in this case, equality should not change if a computer is connected to the Internet versus standalone.
From the URI equals documentation :
For two hierarchical URIs to be considered equal, their paths must be equal and their queries must either both be undefined or else be equal.
In your case, the two path are different. one is "/" the other is "".
According to the URI RFC §6.2.3:
Implementations may use scheme-specific rules, at further processing cost, to reduce the probability of false negatives. For example, because the "http" scheme makes use of an authority component, has a default port of "80", and defines an empty path to be equivalent to "/", the following four URIs are equivalent:
http://example.com http://example.com/ http://example.com:/ http://example.com:80/
It seems that this implementation doesn't use scheme-specific rules.
Resources :
Strictly speaking they are not equal. The optional trailing slash (/) is only a common usage but not a must. You could display different pages for
http://www.yahoo.com/foo/
and for
http://www.yahoo.com/foo
It's even possible for the one you provided I believe the HTTP header could skip that slash.