I know how to add an onClick listener to a LinearLayout to make the whole layout a click target, but I\'d like to have the LinearLayout get highlighted when tapped just like a l
I prefer a simpler way:
<LinearLayout android:orientation="vertical"
android:id="@+id/layoutIdentifier"
android:clickable="true"
android:background="?android:attr/selectableItemBackground"
android:layout_width="match_parent"
android:layout_height="match_parent">
<!-- put views here -->
</LinearLayout>
You can't change the state-pressed background this way, but sometimes you don't really need to.
You can set all the elements inside the layout clickable=false. Then you should mimic selection behavior by setting layout background to some color and set all the other ones with background transparent when a layout is clicked. You can use layout id as index to know which layout is selected.
I ran into this and this is what I came up with. In your layout, set the background to a drawable resource:
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/clickable_layout"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:background="@drawable/clickable">
...
</LinearLayout>
Then in drawable, add clickable.xml as so:
<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item android:state_pressed="true"
android:drawable="@android:drawable/list_selector_background" />
</selector>
Then it's up to you whether or not you want to add a click handler in your activity.