RxJs: poll until interval done or correct data received

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时光取名叫无心 2021-02-02 09:48

How do i execute the following scenario in the browser with RxJs:

  • submit data to queue for processing
  • get back the job id
  • poll another endpoint e
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5条回答
  • 2021-02-02 10:29

    A small optimization to the excellent answer from @matt-burnell. You can replace the filter and take operators with the first operator as follows

    Rx.Observable
      .fromPromise(submitJobToQueue(jobData))
      .flatMap(jobQueueData =>
        Rx.Observable.interval(1000)
          .flatMap(() => pollQueueForResult(jobQueueData.jobId))
          .first(x => x.completed)
          .map(() => 'Completed')
          .timeout(60000, Rx.Observable.throw(new Error('Timeout')))
    
      )
      .subscribe(
        x => console.log('Result', x),
        x => console.log('Error', x)
      );
    

    Also, for people that may not know, the flatMap operator is an alias for mergeMap in RxJS 5.0.

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  • 2021-02-02 10:48

    Not your question, but I needed the same functionality

    import { takeWhileInclusive } from 'rxjs-take-while-inclusive'
    import { of, interval, race, throwError } from 'rxjs'
    import { catchError, timeout, mergeMap, delay, switchMapTo } from 'rxjs/operators'
    
    const defaultMaxWaitTimeMilliseconds = 5 * 1000
    
    function isAsyncThingSatisfied(result) {
      return true
    }
    
    export function doAsyncThingSeveralTimesWithTimeout(
      doAsyncThingReturnsPromise,
      maxWaitTimeMilliseconds = defaultMaxWaitTimeMilliseconds,
      checkEveryMilliseconds = 500,
    ) {
      const subject$ = race(
        interval(checkEveryMilliseconds).pipe(
          mergeMap(() => doAsyncThingReturnsPromise()),
          takeWhileInclusive(result => isAsyncThingSatisfied(result)),
        ),
        of(null).pipe(
          delay(maxWaitTimeMilliseconds),
          switchMapTo(throwError('doAsyncThingSeveralTimesWithTimeout timeout'))
        )
      )
    
      return subject$.toPromise(Promise) // will return first result satistieble result of doAsyncThingReturnsPromise or throw error on timeout
    }
    

    Example

    // mailhogWaitForNEmails
    import { takeWhileInclusive } from 'rxjs-take-while-inclusive'
    import { of, interval, race, throwError } from 'rxjs'
    import { catchError, timeout, mergeMap, delay, switchMap } from 'rxjs/operators'
    
    const defaultMaxWaitTimeMilliseconds = 5 * 1000
    
    export function mailhogWaitForNEmails(
      mailhogClient,
      numberOfExpectedEmails,
      maxWaitTimeMilliseconds = defaultMaxWaitTimeMilliseconds,
      checkEveryMilliseconds = 500,
    ) {
      let tries = 0
    
      const mails$ = race(
        interval(checkEveryMilliseconds).pipe(
          mergeMap(() => mailhogClient.getAll()),
          takeWhileInclusive(mails => {
            tries += 1
            return mails.total < numberOfExpectedEmails
          }),
        ),
        of(null).pipe(
          delay(maxWaitTimeMilliseconds),
          switchMap(() => throwError(`mailhogWaitForNEmails timeout after ${tries} tries`))
        )
      )
    
      // toPromise returns promise which contains the last value from the Observable sequence.
      // If the Observable sequence is in error, then the Promise will be in the rejected stage.
      // If the sequence is empty, the Promise will not resolve.
      return mails$.toPromise(Promise)
    }
    
    // mailhogWaitForEmailAndClean
    import { mailhogWaitForNEmails } from './mailhogWaitForNEmails'
    
    export async function mailhogWaitForEmailAndClean(mailhogClient) {
      const mails = await mailhogWaitForNEmails(mailhogClient, 1)
    
      if (mails.count !== 1) {
        throw new Error(
          `Expected to receive 1 email, but received ${mails.count} emails`,
        )
      }
    
      await mailhogClient.deleteAll()
    
      return mails.items[0]
    }
    
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  • 2021-02-02 10:49

    We also have the same use case and the below code works pretty good.

    import { timer, Observable } from "rxjs";
    import { scan, tap, switchMapTo, first } from "rxjs/operators";
    
    function checkAttempts(maxAttempts: number) {
      return (attempts: number) => {
        if (attempts > maxAttempts) {
          throw new Error("Error: max attempts");
        }
      };
    }
    
    export function pollUntil<T>(
      pollInterval: number,
      maxAttempts: number,
      responsePredicate: (res: any) => boolean
    ) {
      return (source$: Observable<T>) =>
        timer(0, pollInterval).pipe(
          scan(attempts => ++attempts, 0),
          tap(checkAttempts(maxAttempts)),
          switchMapTo(source$),
          first(responsePredicate)
        );
    }
    

    if the number of attempts has reached the limit, an error is thrown which results in the output stream being unsubscribed. Moreover, you only make http requests until the given condition defined as responsePredicate is not met.

    Exemplary usage:

    import { of } from "rxjs";
    
    import { pollUntil } from "./poll-until-rxjs";
    
    const responseObj = { body: { inProgress: true } };
    const response$ = of(responseObj);
    // this is to simulate a http call
    response$
      .pipe(pollUntil(1000, 3, ({ body }) => !body.inProgress))
      .subscribe(({ body }) => console.log("Response body: ", body));
    
    setTimeout(() => (responseObj.body.inProgress = false), 1500);
    
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  • Angular / typescript rewritten solution from above:

    export interface PollOptions {
      interval: number;
      timeout: number;
    }
    
    const OPTIONS_DEFAULT: PollOptions = {
      interval: 5000,
      timeout: 60000
    };
    
    @Injectable()
    class PollHelper {
      startPoll<T>(
        pollFn: () => Observable<T>, // intermediate polled responses
        stopPollPredicate: (value: T) => boolean, // condition to stop polling
        options: PollOptions = OPTIONS_DEFAULT): Observable<T> {
        return interval(options.interval)
          .pipe(
            exhaustMap(() => pollFn()),
            first(value => stopPollPredicate(value)),
            timeout(options.timeout)
          );
      }
    }
    

    Example:

    pollHelper.startPoll<Response>(
      () => httpClient.get<Response>(...),
      response => response.isDone()
    ).subscribe(result => {
      console.log(result);
    });
    
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  • 2021-02-02 10:52

    Starting from the top, you've got a promise that you turn into an observable. Once this yields a value, you want make a call once per second until you receive a certain response (success) or until a certain amount of time has passed. We can map each part of this explanation to an Rx method:

    "Once this yields a value" = map/flatMap (flatMap in this case because what comes next will also be observables, and we need to flatten them out)

    "once per second" = interval

    "receive a certain response" = filter

    "or" = amb

    "certain amount of time has passed" = timer

    From there, we can piece it together like so:

    Rx.Observable
      .fromPromise(submitJobToQueue(jobData))
      .flatMap(jobQueueData =>
        Rx.Observable.interval(1000)
          .flatMap(() => pollQueueForResult(jobQueueData.jobId))
          .filter(x => x.completed)
          .take(1)
          .map(() => 'Completed')
          .amb(
            Rx.Observable.timer(60000)
              .flatMap(() => Rx.Observable.throw(new Error('Timeout')))
          )
      )
      .subscribe(
        x => console.log('Result', x),
        x => console.log('Error', x)
      )
    ;
    

    Once we've got our initial result, we project that into a race between two observables, one that will yield a value when it receives a successful response, and one that will yield a value when a certain amount of time has passed. The second flatMap there is because .throw isn't present on observable instances, and the method on Rx.Observable returns an observable which also needs to be flattened out.

    It turns out that the amb / timer combo can actually be replaced by timeout, like so:

    Rx.Observable
      .fromPromise(submitJobToQueue(jobData))
      .flatMap(jobQueueData =>
        Rx.Observable.interval(1000)
          .flatMap(() => pollQueueForResult(jobQueueData.jobId))
          .filter(x => x.completed)
          .take(1)
          .map(() => 'Completed')
          .timeout(60000, Rx.Observable.throw(new Error('Timeout')))
      )
      .subscribe(
        x => console.log('Result', x),
        x => console.log('Error', x)
      )
    ;
    

    I omitted the .delay you had in your sample as it wasn't described in your desired logic, but it could be fitted trivially to this solution.

    So, to directly answer your questions:

    1. In the code above there is no need to manually stop anything, as the interval will be disposed of the moment the subscriber count drops to zero, which will occur either when the take(1) or amb / timeout completes.
    2. Yes, both usages in your original were valid, as in both cases you were projecting each element of an observable into a new observable, and wanting to flatten the resultant observable of observables out into a regular observable.

    Here's the jsbin I threw together to test the solution (you can tweak the value returned in pollQueueForResult to obtain the desired success/timeout; times have been divided by 10 for the sake of quick testing).

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