Serializing Entity Relation only to Id with JMS Serializer

Question

I\'m trying to serialize a entity relation with JMS Serializer.

Here is the Entity:

class Ad
{ 

    /**
     * @Type(\"string\")
     * @Groups({\"manag         


        

Answer 1

I know this has already been answered but you could also use @Accessor. This probably (may, I can't be sure) work with deserialization too.

/**
 * @Type("Acme\SearchBundle\Entity\Country")
 * @Groups({"manage"})
 * 
 * @var \Acme\SearchBundle\Entity\Country
 *
 * @Serializer\Accessor(getter="getCountryMinusId",setter="setCountryWithId")
 */
private $country;

/**
 * @return string|null
 */
public function getCountryMinusId()
{
    if (is_array($this->country) && isset($this->country['id'])) {
        return $this->country['id'];
    }

    return null;
}

/**
 * @param string $country
 * @return $this
 */
public function setCountryWithId($country)
{
    if (!is_array($this->country)) {
        $this->country = array();
    )

    $this->country['id'] = $country;

    return $this;
}

Answer 2

Yes, you could use @VirtualProperty annotation:

/**
 * @VirtualProperty
 * @SerializedName("foo")
 */
public function bar()
{
    return $this->country->getCode();
}

But be aware when it comes to deserialization:

@VirtualProperty This annotation can be defined on a method to indicate that the data returned by the method should appear like a property of the object.

> Note: This only works for serialization and is completely ignored during deserialization.

Hope this helps...

Answer 3

You can use @Type and @Accessor annotations:

/**
 * @Type("string") 
 * @Accessor(getter="serializeType",setter="setType") 
 */
protected $type;
public function serializeType()
{   
  return $this->type->getId();
}

Answer 4

Just to follow answered question:

If you don't like writing one method for each relation you have - just write your own handler. It's easy like

final class RelationsHandler
{
    /**
     * @var EntityManagerInterface
     */
    private $manager;

    /**
     * RelationsHandler constructor.
     *
     * @param EntityManagerInterface $manager
     */
    public function __construct(EntityManagerInterface $manager) { $this->manager = $manager; }


    public function serializeRelation(JsonSerializationVisitor $visitor, $relation, array $type, Context $context)
    {
        if ($relation instanceof \Traversable) {
            $relation = iterator_to_array($relation);
        }

        if (is_array($relation)) {
            return array_map([$this, 'getSingleEntityRelation'], $relation);
        }

        return $this->getSingleEntityRelation($relation);
    }

    /**
     * @param $relation
     *
     * @return array|mixed
     */
    protected function getSingleEntityRelation($relation)
    {
        $metadata = $this->manager->getClassMetadata(get_class($relation));

        $ids = $metadata->getIdentifierValues($relation);
        if (!$metadata->isIdentifierComposite) {
            $ids = array_shift($ids);
        }

        return $ids;
    }
}

Register the Handler

  jms_serializer.handler.relation:
      class: MyBundle\RelationsHandler
      arguments:
      - "@doctrine.orm.entity_manager"
      tags:
      - { name: jms_serializer.handler, type: Relation, direction: serialization, format: json, method: serializeRelation}
      - { name: jms_serializer.handler, type: Relation, direction: deserialization, format: json, method: deserializeRelation}
      - { name: jms_serializer.handler, type: Relation<?>, direction: serialization, format: json, method: serializeRelation}
      - { name: jms_serializer.handler, type: Relation<?>, direction: deserialization, format: json, method: deserializeRelation}

This allows you to replace virtual getter methods with `Type("Relation").

If you also want't to deserialize relation - you should tell each @Type("Relation") the classname (@Type("Relation<FQCN>")) which it should deserialize to or wrap the metadata driver with one which do it for you.

    public function deserializeRelation(JsonDeserializationVisitor $visitor, $relation, array $type, Context $context)
    {
        $className = isset($type['params'][0]['name']) ? $type['params'][0]['name'] : null;

        if (!class_exists($className, false)) {
            throw new \InvalidArgumentException('Class name should be explicitly set for deserialization');
        }

        $metadata = $this->manager->getClassMetadata($className);

        if (!is_array($relation)) {
            return $this->manager->getReference($className, $relation);
        }

        $single = false;
        if ($metadata->isIdentifierComposite) {
            $single = true;
            foreach ($metadata->getIdentifierFieldNames() as $idName) {
                $single = $single && array_key_exists($idName, $relation);
            }
        }

        if ($single) {
            return $this->manager->getReference($className, $relation);
        }

        $objects = [];
        foreach ($relation as $idSet) {
            $objects[] = $this->manager->getReference($className, $idSet);
        }

        return $objects;
    }

Answer 5

Alternatively, you can @inline $country which will serialize its properties into the parent relation. Then you can @Expose the Country $id and set its @SerializedName to "country". Unlike Virtual properties, both serialization and deserialization will work for inline properties.

For this to work, you need to use the @ExclusionPolicy("All") on each class and judiciously @Expose the properties that you need in any of your groups. This is a more secure policy anyways.

/**
 * @ExclusionPolicy("All")
 */
class Ad
{ 

    //...


    /**
     * @Type("Acme\SearchBundle\Entity\Country")
     * 
     * @Expose()
     * @Inline()
     * @Groups({"manage"})
     *
     * @var \Acme\SearchBundle\Entity\Country
     */
    private $country;


    //...

}

/**
 * @ExclusionPolicy("All")
 */
class Country
{

    //...

    /**
     * Get id
     *
     * @Expose()
     * @Groups({"manage"})
     * @SerializedName("country")
     * @return string 
     */
    public function getId()
    {
        return $this->id;
    }
}

Answer 6

The author wants to keep the property name, which doesn't apply to the accepted answer. As far as I understood, the answer by ScayTrase would keep the original property name but has another disadvantage according to the comments: The related object will be fetched if you are using Doctrine ORM @ManyToOne, thus decreasing performance.

If you want to keep the original property name, you have to define the @VirtualProperty at class level and @Exclude the original property. Otherwise, the serialized property name will be derived from the getter method (countryId in this case):

/**
 * @Serializer\VirtualProperty(
 *     "country",
 *     exp="object.getCountryId()",
 *     options={@Serializer\SerializedName("country")}
 * )
 */
class Ad {
    /**
     * @Serializer\Exclude
     */
    private $country;

    public function getCountryId() {
        return $this->country === null ? null : $this->country->getId();
    }
}