How can I return a JSON result to a Ajax.BeginForm

Question

I have got this simple form:

@using (Ajax.BeginForm(\"CreateProductFromAjaxForm\",\"Product\" , 
                  null, 
                  new AjaxOptions() {           


        

Answer 1

JsonResult is just a kind of ActionResult derived class that indicates that this action will return JSON instead of a view or something else.

For example:

 @using (Ajax.BeginForm("CreateProductFromAjaxForm","Product" , null, 
              new AjaxOptions() {  OnSuccess = "getresult" }, null))

This will generate a element which will send an AJAX request when submitted to the action. For this to work you need to include the following script to your page:

Now all that's left is to write this onSuccess javascript function and process the JSON results returned by the server:

<script type="text/javascript">
var onSuccess = function(data) {
    alert(data.result);
};
</script

Answer 2

Instead of:

var getresult = function (data) {
    alert(data.result);
};

Try

function getresult(data) {
    alert(data.result);
};

Answer 3

I faced the same issue with my project. Ajax library is not being loaded is the problem. When I checked my bundleconfig and my layout file, it did have the include but I'm including the absolute name for ajax library like

bundles.Add(new ScriptBundle("~/bundles/jqueryajax").Include(
"~/Scripts/jquery.unobtrusive-ajax.min.js"));

My friend asked me to use the wild card instead. Surprisingly bundles.Add(new ScriptBundle("~/bundles/jqueryajax").Include("~/Scripts/jquery.unobtrusive-ajax*")); started including the ajax library.

Now my OnSuccess functions are loading as expected rather than looking at the blank screen with json response on it.

Answer 4

you need to include jquery.unobtrusive-ajax.js file.

<script src="~/Scripts/jquery.unobtrusive-ajax.js"></script>

Answer 5

Try specifying the HTTP method:

new AjaxOptions() {  
    OnSuccess = "getresult", 
    HttpMethod = "post" 
}

Example:

@using (Ajax.BeginForm("CreateProductFromAjaxForm", "Product" , null, new AjaxOptions() {  OnSuccess = "getresult", HttpMethod = "post" }, null))
{
    ....
}

Answer 6

in page

new AjaxOptions() {  
    OnSuccess = "getresult", 
}

in javascript

function getresult(data){
   alert(data.x);
}

in c#

[HttpPost]
public ActionResult CreateProductFromAjaxForm(CreateProductModel model)
{
    if (!ModelState.IsValid)
    {
        return Json("error", JsonRequestBehavior.AllowGet);
    }

   //add to database

    return Json(model, JsonRequestBehavior.AllowGet);
}