How to check if a word is present in a sentence using Java? [duplicate]

Answer 1

This will work, assuming that each word is separated by a space. I've added the main function for clarity. The find_str returns -1 if the word doesn't exist. otherwise, it returns the position of the word with respect to other words. Here, 2 will be returned, meaning that the second word is 'am'.

import java.util.*;
public class HelloWorld{

    public static void main(String []args){
        String str="I am a Java Programmer";
        String str1="am";
        int x=find_str(str,str1);
        System.out.println(x);

    }

    public static int find_str(String main,String search) {

        int i; 
        int found=-1;

        String[] s=main.split(" ");
        for(i=0;i<s.length;i++)
        {
            if(search.equals(s[i]))
            found=i+1;
        }
        return found;
    }
}

Answer 2

use contains method

boolean isPresent(String word, String sentence)
{
return sentence.contains(word);   
}

EDIT: if you want to search for a pariticular word then you can add space befaore and after the word string
word = " " + word + " ";

Answer 3

try regex

boolean contains = s.matches(".*\\bram\\b.*");

\b means word boundary

Answer 4

String s="I am a JAVA programmer";
    String s1="JAVA";
    String []p=s.split("\\s*(=>|,|\\s)\\s*");
        for(int i=0;i<p.length;i++)
        {
            if(s1.equals(p[i]))
            {
                System.out.println(p[i]);
            }

        }

Answer 5

Try this solution

    int index = sent.indexOf(find);
    if (index != -1) {
        if (index == 0) {
            System.out.println("true");
        }
        else if (index + find.length() == sent.length())
        {
            System.out.println("true");
        }
        else if (sent.charAt(index - 1) == ' ' && sent.charAt(find.length() + index) == ' ') {
            System.out.println("true");
        } else {
            System.out.println("false");
        }

    } else {
        System.out.println("false");
    }

If you want something more than you original question then instead for checking for spaces you should check that they are not between 0-9 and a-Z, this should cover any characters such as comma period etc.

Answer 6

A more simpler approach is: if you consider that a word is something like

"My pc there is ram memory" (between spaces)

you could concat into your indexOf function spaces before and after the word that you are searching, like this

if (sentence.indexOf(" "+ word +" ") >= 0) {