C++ namespace alias in entire class scope

Question

I expected to be able to use a namespace alias in a class declaration but get a compiler syntax error.

struct MyClass
{
    namespace abc = a_big_namespace;
             


        

Answer 1

You can of course also put the alias outside the class:

namespace abc = a_big_namespace;     

struct MyClass {
    void fn()
    { abc::test(); } 
}; 

Answer 2

It works if you declare the alias outside of the struct.

Answer 3

The scope of a namespace alias is a code block.

So you can put it in any code block.

BUT, you can't put it inside a class, because that will mean it's a member of the class.
A namespace alias can't be a member.

More about namespace aliases:

What is the scope of a namespace alias in C++?
Namespaces

Answer 4

Namespace alias in the class definition is illegal, as specified by the language specification.

Its allowed in only in namespace scope or function scope.

You can make alias at namespace scope. But that will be make permanent alias which can be used from other files as well. But the solution is simple : you can use unnamed namespace to prevent alias (and therefore all symbols from the big namespace) from being visible from other files. This is how it can be done:

//MyFile.cpp
namespace myspace
{ 
    namespace   //this is unnamed namespace
    {
       namespace abc = a_big_namespace;     
    }
    struct MyClass 
    {
      void fn() 
      { 
         abc::test();  //don't worry, this will work!
      } 
    };
}

//OtherFile.cpp

myspace::abc::test(); //error - that means, prevention worked.

The alias is not visible from other files. When compiling OtherFile.cpp, GCC (4.5.0) says,

'myspace::abc' has not been declared

That proves the alias abc is visible only in MyFile.cpp. Thanks to unnamed namespace.

Demo : http://www.ideone.com/2zyNI (though it doesn't demonstrate OtherFile concept. I cannot have more than one file at ideone.com)