I found the is_visible method in the Selenium documentation, but I have no idea how to use it. I keep getting errors such as is_visible needs a selenium instance as the fi
You should use is_displayed()
instead:
from selenium import webdriver
driver = webdriver.Firefox()
driver.get('http://www.google.com')
element = driver.find_element_by_id('gbqfba') #this element is visible
if element.is_displayed():
print "Element found"
else:
print "Element not found"
hidden_element = driver.find_element_by_name('oq') #this one is not
if hidden_element.is_displayed():
print "Element found"
else:
print "Element not found"
From here: https://www.selenium.dev/selenium/docs/api/py/webdriver_support/selenium.webdriver.support.expected_conditions.html
Just use
selenium.webdriver.support.expected_conditions.visibility_of
cos
Visibility means that the element is not only displayed but also has a height and width that is greater than 0