Create excel ranges using column numbers in vba?

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误落风尘
误落风尘 2021-02-02 05:56

How is it possible to create a range in vba using the column number, rather than letter?

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  • 2021-02-02 06:09

    In case you were looking to transform your column number into a letter:

    Function ConvertToLetter(iCol As Integer) As String
        Dim iAlpha As Integer
        Dim iRemainder As Integer
        iAlpha = Int(iCol / 27)
        iRemainder = iCol - (iAlpha * 26)
        If iAlpha > 0 Then
            ConvertToLetter = Chr(iAlpha + 64)
        End If
        If iRemainder > 0 Then
            ConvertToLetter = ConvertToLetter & Chr(iRemainder + 64)
        End If
    End Function
    

    This way you could do something like this:

    Function selectColumnRange(colNum As Integer, targetWorksheet As Worksheet)
        Dim colLetter As String
        Dim testRange As Range
        colLetter = ConvertToLetter(colNum)
        testRange = targetWorksheet.Range(colLetter & ":" & colLetter).Select
    End Function
    

    That example function would select the entire column ( i.e. Range("A:A").Select)

    Source: http://support.microsoft.com/kb/833402

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  • 2021-02-02 06:12

    Below are two solutions to select the range A1.

    Cells(1,1).Select '(row 1, column 1) 
    Range("A1").Select
    

    Also check out this link;

    • http://www.excel-vba.com/vba-code-2-6-cells-ranges.htm

    We strongly recommend that you use Range instead of Cells to work with cells and groups of cells. It makes your sentences much clearer and you are not forced to remember that column AE is column 31.

    The only time that you will use Cells is when you want to select all the cells of a worksheet. For example: Cells.Select To select all cells and then empty all cells of values or formulas you will use: Cells.ClearContents

    --

    "Cells" is particularly useful when setting ranges dynamically and looping through ranges by using counters. Defining ranges using letters as column numbers may be more transparent on the short run, but it will also make your application more rigid since they are "hard coded" representations - not dynamic.

    Thanks to Kim Gysen

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  • 2021-02-02 06:14

    I really like stackPusher's ConvertToLetter function as a solution. However, in working with it I noticed several errors occurring at very specific inputs due to some flaws in the math. For example, inputting 392 returns 'N\', 418 returns 'O\', 444 returns 'P\', etc.

    I reworked the function and the result produces the correct output for all input up to 703 (which is the first triple-letter column index, AAA).

    Function ConvertToLetter2(iCol As Integer) As String
        Dim First As Integer
        Dim Second As Integer
        Dim FirstChar As String
        Dim SecondChar As String
    
        First = Int(iCol / 26)
        If First = iCol / 26 Then
            First = First - 1
        End If
        If First = 0 Then
            FirstChar = ""
        Else
            FirstChar = Chr(First + 64)
        End If
    
        Second = iCol Mod 26
        If Second = 0 Then
            SecondChar = Chr(26 + 64)
        Else
            SecondChar = Chr(Second + 64)
        End If
    
        ConvertToLetter2 = FirstChar & SecondChar
    
    End Function
    
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  • 2021-02-02 06:14
    Function fncToLetters(vintCol As Integer) As String
    
            Dim mstrDigits As String
    
        ' Convert a positive number n to its digit representation in base 26.
        mstrDigits = ""
        Do While vintCol > 0
            mstrDigits = Chr(((vintCol - 1) Mod 26) + 65) & mstrDigits
            vintCol = Int((vintCol - 1) / 26)
        Loop
    
        fncToLetters = mstrDigits
    
    End Function
    
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  • 2021-02-02 06:19

    Range.EntireColumn

    Yes! You can use Range.EntireColumn MSDN

    dim column : column = 4
    
    dim column_range : set column_range = Sheets(1).Cells(column).EntireColumn
    

    Range("ColumnName:ColumnName")

    If you were after a specific column, you could create a hard coded column range with the syntax e.g. Range("D:D").

    However, I'd use entire column as it provides more flexibility to change that column at a later time.

    Worksheet.Columns

    Worksheet.Columns provides Range access to a column within a worksheet. MSDN

    If you would like access to the first column of the first sheet. You would call the Columns function on the worksheet.

    dim column_range: set column_range = Sheets(1).Columns(1)
    

    The Columns property is also available on any Range MSDN

    EntireRow can also be useful if you have a range for a single cell but would like to reach other cells on the row, akin to a LOOKUP

    dim id : id = 12345
    
    
    dim found : set found = Range("A:A").Find(id)
    
    if not found is Nothing then
        'Get the fourth cell from the match
        MsgBox found.EntireRow.Cells(4)
    end if
    
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  • 2021-02-02 06:20

    To reference range of cells you can use Range(Cell1,Cell2), sample:

    Sub RangeTest()
      Dim testRange As Range
      Dim targetWorksheet As Worksheet
      
      Set targetWorksheet = Worksheets("MySheetName")
      
      With targetWorksheet
        .Cells(5, 10).Select 'selects cell J5 on targetWorksheet
        Set testRange = .Range(.Cells(5, 5), .Cells(10, 10))
      End With
      
      testRange.Select 'selects range of cells E5:J10 on targetWorksheet
      
    End Sub
    

    enter image description here

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