finding first day of the month in python

Question

I\'m trying to find the first day of the month in python with one condition: if my current date passed the 25th of the month, then the first date variable will hold the first da

Answer 1

This is a pithy solution.

import datetime 

todayDate = datetime.date.today()
if todayDate.day > 25:
    todayDate += datetime.timedelta(7)
print todayDate.replace(day=1)

One thing to note with the original code example is that using timedelta(30) will cause trouble if you are testing the last day of January. That is why I am using a 7-day delta.

Answer 2

This could be an alternative to Gustavo Eduardo Belduma's answer:

import datetime 
first_day_of_the_month = datetime.date.today().replace(day=1)

Answer 3

You can use dateutil.rrule:

In [1]: from dateutil.rrule import *

In [2]: rrule(DAILY, bymonthday=1)[0].date()
Out[2]: datetime.date(2018, 10, 1)

In [3]: rrule(DAILY, bymonthday=1)[1].date()
Out[3]: datetime.date(2018, 11, 1)

Answer 4

Can be done on the same line using date.replace:

from datetime import datetime

datetime.today().replace(day=1)

Answer 5

Use arrow.

import arrow
arrow.utcnow().span('month')[0]