Converting a str to a &[u8]

Question

This seems trivial, but I cannot find a way to do it.

For example,

fn f(s: &[u8]) {}

pub fn main() {
    let x = \"a\";
    f(x)
}

Answer 1

You can use the as_bytes method:

fn f(s: &[u8]) {}

pub fn main() {
    let x = "a";
    f(x.as_bytes())
}

or, in your specific example, you could use a byte literal:

let x = b"a";
f(x)