Scala: Boolean to Option

Question

I have a Boolean and would like to avoid this pattern:

if (myBool) 
  Option(someResult) 
else 
  None

What I\'d like to do is

Answer 1

Option(true).find(_ == true) // Some(true)
Option(false).find(_ == true) // None

Answer 2

Option().collect() is a good pattern for this kind of thing.

Option(myBool).collect { case true => someResult }

from the REPL:

scala> (Option(true).collect { case true => 3 }, Option(false).collect { case true => 3 })
res3: (Option[Int], Option[Int]) = (Some(3),None)

Answer 3

If you don't mind someResult being evaluated no matter the value of myBool you can also use

Some(someResult).filter(myBool)

Answer 4

None of the other answers answer the question as stated! To get the exact semantics you specified use:

implicit class BoolToOption(val self: Boolean) extends AnyVal {
  def toOption[A](value: => A): Option[A] =
    if (self) Some(value) else None
}

You can then write

myBool.toOption(someResult)

eg:

scala> true.toOption("hi")
res5: Option[String] = Some(hi)

scala> false.toOption("hi")
res6: Option[String] = None