Facebook - obtain location /places ID via location name

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囚心锁ツ
囚心锁ツ 2021-02-01 22:51

I\'m able to return a location\'s details by sending a query via the graph api with the location\'s ID, however I\'m looking to achieve the reverse - effectively find location i

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  • 2021-02-01 23:05

    If I understand your question correctly you can use fql: https://api.facebook.com/method/fql.query?query=QUERY where query should be something like this: select page_id from place where name = ;

    Here is a page for your refrence: http://developers.facebook.com/docs/reference/fql/place/

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  • 2021-02-01 23:13

    You also can use the place sdk from facebook:

    compile group: 'com.facebook.android', name: 'facebook-places', version: '4.30.0' // For latest version, see https://developers.facebook.com/docs/android/

    and then:

    PlaceSearchRequestParams.Builder builder = new PlaceSearchRequestParams.Builder();
    
    builder.setSearchText("Cafe");
    builder.setDistance(1000); // 1,000 meter maximum distance.
    builder.setLimit(10);
    builder.addField(PlaceFields.ID);
    
    GraphRequest request = PlaceManager.newPlaceSearchRequestForLocation(builder.build());
    
    request.setCallback(new GraphRequest.Callback() {
        @Override
        public void onCompleted(GraphResponse response) {
            // Handle the response. The returned ID in JSON is the placeId.
        }
    
    request.executeAsync();
    
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  • 2021-02-01 23:20

    This is possible under a few different approaches. You can either search using long / lat positions and put the place name into the query. This search will search places only.

    Do the following

    https://graph.facebook.com/search?q=ritual&type=place&center=37.76,-122.427&distance=1000&access_token=mytoken.

    This will return ritual coffee.

    Another way is to search through facebook pages using the following https://graph.facebook.com/search?q=ritual%20coffee&type=page&access_token=mytoken

    This way is more difficult as you will obviously need to parse the list in more detail.

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