Get length of a video using regex and ffmpeg

Question

From the following ffmpeg -i output, how would I get the length (00:35)--

$ ffmpeg -i 1video.mp4

Input #0, mov,mp4,m4a,3gp,3g2,mj2, from \'/Users/d         


        

Answer 1

You can use the shell

$ ff=$(ffmpeg -i video.mp4 2>&1)
$ d="${ff#*Duration: }"
$ echo "${d%%,*}"

Answer 2

Do you want to do this in a bare shell pipeline, or read the result in a calling program?

/\s+Duration: ((\d\d):(\d\d):(\d\d)\.(\d+))/

… is a PCRE that will split the result up (replace the \. with [;:.] if ffmpeg might output the duration in frames rather than fractional seconds). In a Unix pipeline:

| grep Duration: | cut -f2- -d: | cut -f1 -d, | tr -d ' '

There are of course a billion other ways to express this.

Answer 3

Duration: (\d\d):(\d\d):(\d\d(\.\d\d)?)

should work. Whatever your language's $1 is will be the hours, $2 will be the minutes, $3 will be the seconds, and $4 will be just the centiseconds if they are exist.

Answer 4

This way you get the duration in seconds. I think this is more convenient.

ffprobe -loglevel error -show_streams inputFile.mp3 | grep duration | cut -f2 -d=

ffprobe comes with ffmpeg so you should have it.

EDIT: For a more dedicated version you could use for example

ffprobe -loglevel error -show_format -show_streams inputFile.extension -print_format json

Instead of JSON you could also use e.g. CSV or XML. For more output options look here http://ffmpeg.org/ffprobe.html#Writers

Answer 5

Format (container) duration:

$ ffprobe -v error -show_entries format=duration -of default=noprint_wrappers=1:nokey=1 input.mp4
30.024000

Adding the -sexagesimal option will use the HOURS:MM:SS.MICROSECONDS time unit format:

0:00:30.024000

Duration of the first video stream:

$ ffprobe -v error -select_streams v:0 -show_entries stream=duration -of default=noprint_wrappers=1:nokey=1 input.mp4
30.000000

https://trac.ffmpeg.org/wiki/FFprobeTips#Duration

Answer 6

for latest version :

$cmd = "avconv -i input.mp4 2>&1 | grep Duration | awk '{print $2}' | tr -d ,";
$output = exec($cmd);
echo "\n\n==OUTPUT===|".$output."|=====\n\n";

Now $output will hold your duration of video input.mp4

format will be: hh:mm:ss.ms

e.g 00:02:17.25