I want to get youtube highest thumbnail \"maxresdefault.jpg\"
Like this one
http://i.ytimg.com/vi/Cj6ho1-G6tw/maxresdefault.jpg
I\'m using this simple ph
Thanks to Ibrahim Ulukaya's answer I was able to understand why David Chen's previously correct answer no longer works; Google has deprecated that prior working API. (Wicked, bad, naughty, evil, Google.)
The following URL will return a list of thumbnail objects using the Data API v3:
https://www.googleapis.com/youtube/v3/videos?id={VIDEO_ID}&key={API_KEY}&part=snippet&fields=items/snippet/thumbnails
The {VIDEO_ID}
can be found as part of any YouTube video URL and the {API_KEY}
requires you to:
Once you have the URL with your VIDEO_ID
and API_KEY
substituted for the placeholders you should get back JSON that looks something like this:
{
"items": [
{
"snippet": {
"thumbnails": {
"default": {
"url": "https://i.ytimg.com/vi/7Ey-Xkwn1s0/default.jpg",
"width": 120,
"height": 90
},
"medium": {
"url": "https://i.ytimg.com/vi/7Ey-Xkwn1s0/mqdefault.jpg",
"width": 320,
"height": 180
},
"high": {
"url": "https://i.ytimg.com/vi/7Ey-Xkwn1s0/hqdefault.jpg",
"width": 480,
"height": 360
},
"standard": {
"url": "https://i.ytimg.com/vi/7Ey-Xkwn1s0/sddefault.jpg",
"width": 640,
"height": 480
},
"maxres": {
"url": "https://i.ytimg.com/vi/7Ey-Xkwn1s0/maxresdefault.jpg",
"width": 1280,
"height": 720
}
}
}
}
]
}
From there I am guessing you'll know what to do...?
Hope this helps.
You can use getimagesize()
and check if the image exists (there's file_exists()
too, but it may not work very well, in this case).
You can use this function to fetch the greatest resolution screenshot of a particular video.
Code:
function fetch_highest_res ($videoid) {
$resolutions = array('maxresdefault', 'hqdefault', 'mqdefault');
foreach($resolutions as $res) {
$imgUrl = "http://i.ytimg.com/vi/$videoid/$res.jpg";
if(@getimagesize(($imgUrl)))
return $imgUrl;
}
}
Usage:
echo fetch_highest_res('Cj6ho1-G6tw').'<br>';
echo fetch_highest_res('VGazSZUYyf4');
Output:
http://i.ytimg.com/vi/Cj6ho1-G6tw/maxresdefault.jpg
http://i.ytimg.com/vi/VGazSZUYyf4/hqdefault.jpg
Note: This may not be the best solution, and it's a work-around if you don't want to use the API.
All the other answers that are dependent on static url scraping are not supported. They can get changed and you may need to change your application at everytime.
For this you should use Data API v3. You should go with a videos->list request with id=videoId and part=snippet. In the response you will check snippet.thumbnails.['high'].url
The reason is because the resolution on Making the Most of Maps is not at least 720p.
Looking at the api for this specific video, you can see that there is no maxresdefault
.
Only videos that are 720p or higher in resolution have maxresdefault
. This is not listed in the API in videos that are higher. So in order to get the highest resolution, you should also check if the maxresdefault
works as well.
<media:thumbnail url='http://i1.ytimg.com/vi/VGazSZUYyf4/default.jpg' height='90' width='120' time='00:15:12.500' yt:name='default'/>
<media:thumbnail url='http://i1.ytimg.com/vi/VGazSZUYyf4/mqdefault.jpg' height='180' width='320' yt:name='mqdefault'/>
<media:thumbnail url='http://i1.ytimg.com/vi/VGazSZUYyf4/hqdefault.jpg' height='360' width='480' yt:name='hqdefault'/>
<media:thumbnail url='http://i1.ytimg.com/vi/VGazSZUYyf4/1.jpg' height='90' width='120' time='00:07:36.250' yt:name='start'/>
<media:thumbnail url='http://i1.ytimg.com/vi/VGazSZUYyf4/2.jpg' height='90' width='120' time='00:15:12.500' yt:name='middle'/>
<media:thumbnail url='http://i1.ytimg.com/vi/VGazSZUYyf4/3.jpg' height='90' width='120' time='00:22:48.750' yt:name='end'/>
Your best bet for the highest quality thumbnail is to use the API and get the image with the largest yt:name
attribute.
The order is:
default
mqdefault
hqdefault
sddefault
Example code of this in action:
<?php
$youtub_id = "VGazSZUYyf4";
$images = json_decode(file_get_contents("http://gdata.youtube.com/feeds/api/videos/".$youtub_id."?v=2&alt=json"), true);
$images = $images['entry']['media$group']['media$thumbnail'];
$image = $images[count($images)-4]['url'];
$maxurl = "http://i.ytimg.com/vi/".$youtub_id."/maxresdefault.jpg";
$max = get_headers($maxurl);
if (substr($max[0], 9, 3) !== '404') {
$image = $maxurl;
}
echo '<img src="'.$image.'">';
This works both on $youtub_id = "Cj6ho1-G6tw";
and $youtub_id = "VGazSZUYyf4";
.