How does the default GLSL shaders look like? for version 330

Question

What do the default vertex, fragment and geometry GLSL shaders look like for version #330?

I\'ll be using #version 330 GLSL Version 3.30 NVIDIA via Cg compi

Answer 1

There are no "default" shaders with OpenGL. It looks like what you want a very simple example of a shader that transforms vertices to clip space and gives them a color, so here you go:

Vertex shader:

#version 330

layout(location = 0)in vec4 vert;

uniform mat4 projection;
uniform mat4 view;
uniform mat4 model;

void main()
{
    gl_Position = projection * view * model * vert;
}

Fragment shader:

#version 330

out vec4 fragColor;

void main()
{
    fragColor = vec4(1.0, 0.0, 0.0, 1.0);
}

The core OpenGL 3.3 profile drops support for a lot of old fixed-function things like the matrix stack. You are expected to handle your own matrices and send them to your shaders. There is no ftransform, and gl_Position is pretty much the only valid gl_* variable.

While glBindAttribLocation is not deprecated, the preferred method of defining the location of vertex attributes is through "layout(location = x)" in GLSL.

In the vertex shader, "attribute" is now "in" and "varying" is now "out". In the fragment shader, "varying" is now "in" and "gl_FragColor" is defined by an "out" variable. I believe that gl_FragColor is still valid, but now it's possible to use an out variable to define the color.

This tutorial is very good and teaches core OpenGL and GLSL 3.30, I would recommend you use it to help you learn more about GLSL. Also remember that the GLSL Reference Pages is your friend.