What is the more elegant way to remove all characters after specific character in the String object in Swift

Question

What is the more elegant way to remove all characters after specific character in the String object in Swift?

Suppose that I have the following string:

Answer 1

Here is a way to do it:

var str = "str.str"

if let dotRange = str.rangeOfString(".") {
    str.removeRange(dotRange.startIndex..<str.endIndex)
}

Update In Swift 3 it is:

var str = "str.str"

if let dotRange = str.range(of: ".") {
  str.removeSubrange(dotRange.lowerBound..<str.endIndex)
}

Answer 2

Swift 5.1

Answer 3

I think this is better approach:

Update with Swift 4: (substring is now deprecated)

let smth = "element=value"

if let index = (smth.range(of: "=")?.upperBound)
{
  //prints "value"
  let afterEqualsTo = String(smth.suffix(from: index))

  //prints "element="
  let beforeEqualsToContainingSymbol = String(smth.prefix(upTo: index))
}

if let index = (smth.range(of: "=")?.lowerBound)
{
  //prints "=value"
  let afterEqualsToContainingSymbol = String(smth.suffix(from: index))

  //prints "element"
  let beforeEqualsTo = String(smth.prefix(upTo: index))
}

Answer 4

Quite a compact way would be:

var str = "str.str"
str = str.componentsSeparatedByString(".")[0]

Another option you might be interested in, which works for your example 'str.str' but doesn't fit your specification is:

str = str.stringByDeletingPathExtension
// Returns a new string made by deleting the extension (if any, and only the last)
// from the `String`