comparing two strings in ruby [closed]

Answer 1

Here are some:

"Ali".eql? "Ali"
=> true

The spaceship (<=>) method can be used to compare two strings in relation to their alphabetical ranking. The <=> method returns 0 if the strings are identical, -1 if the left hand string is less than the right hand string, and 1 if it is greater:

"Apples" <=> "Apples"
=> 0

"Apples" <=> "Pears"
=> -1

"Pears" <=> "Apples"
=> 1

A case insensitive comparison may be performed using the casecmp method which returns the same values as the <=> method described above:

"Apples".casecmp "apples"
=> 0

Answer 2

From what you printed, it seems var2 is an array containing one string. Or actually, it appears to hold the result of running .inspect on an array containing one string. It would be helpful to show how you are initializing them.

irb(main):005:0* v1 = "test"
=> "test"
irb(main):006:0> v2 = ["test"]
=> ["test"]
irb(main):007:0> v3 = v2.inspect
=> "[\"test\"]"
irb(main):008:0> puts v1,v2,v3
test
test
["test"]

Answer 3

Comparison of strings is very easy in Ruby:

v1 = "string1"
v2 = "string2"
puts v1 == v2 # prints false
puts "hello"=="there" # prints false
v1 = "string2"
puts v1 == v2 # prints true

Make sure your var2 is not an array (which seems to be like)

Answer 4

var1 is a regular string, whereas var2 is an array, this is how you should compare (in this case):

puts var1 == var2[0]