Split on different newlines

Question

Right now I\'m doing a split on a string and assuming that the newline from the user is \\r\\n like so:

string.split(/\\r\\n/)
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Answer 1

\n is for unix 
\r is for mac 
\r\n is for windows format

To be safe for operating systems. I would do /\r?\n|\r\n?/

"1\r2\n3\r\n4\n\n5\r\r6\r\n\r\n7".split(/\r?\n|\r\n?/)
=> ["1", "2", "3", "4", "", "5", "", "6", "", "7"]

Answer 2

Are you reading from a file, or from standard in?

If you're reading from a file, and the file is in text mode, rather than binary mode, or you're reading from standard in, you won't have to deal with \r\n - it'll just look like \n.

C:\Documents and Settings\username>irb
irb(main):001:0> gets
foo
=> "foo\n"

Answer 3

Another option is to use String#chomp, which also handles newlines intelligently by itself.

You can accomplish what you are after with something like:

lines = string.lines.map(&:chomp)

Or if you are dealing with something large enough that memory use is a concern:

<string|io>.each_line do |line|
  line.chomp!
  #  do work..
end

Performance isn't always the most important thing when solving this kind of problem, but it is worth noting the chomp solution is also a bit faster than using a regex.

On my machine (i7, ruby 2.1.9):

Warming up --------------------------------------
           map/chomp    14.715k i/100ms
  split custom regex    12.383k i/100ms
Calculating -------------------------------------
           map/chomp    158.590k (± 4.4%) i/s -    794.610k in   5.020908s
  split custom regex    128.722k (± 5.1%) i/s -    643.916k in   5.016150s

Answer 4

Did you try /\r?\n/ ? The ? makes the \r optional.

Example usage: http://rubular.com/r/1ZuihD0YfF

Answer 5

Perhaps do a split on only '\n' and remove the '\r' if it exists?

Answer 6

# Split on \r\n or just \n
string.split( /\r?\n/ )

Although it doesn't help with this question (where you do need a regex), note that String#split does not require a regex argument. Your original code could also have been string.split( "\r\n" ).