Dart List min/max value

Question

How do you get the min and max values of a List in Dart.

[1, 2, 3, 4, 5].min //returns 1
[1, 2, 3, 4, 5].max //returns 5         


        

Answer 1

Assuming the list is not empty you can use Iterable.reduce :

import 'dart:math';

main(){
  print([1,2,8,6].reduce(max)); // 8
  print([1,2,8,6].reduce(min)); // 1
}

Answer 2

Using fold method with dart:math library

Example:

// Main function 
void main() { 
  // Creating a geek list 
  var geekList = [121, 12, 33, 14, 3]; 
    
  // Declaring and assigning 
  // the largestGeekValue and smallestGeekValue 
  // Finding the smallest and 
  // largest value in the list 
  var smallestGeekValue = geekList.fold(geekList[0],min); 
  var largestGeekValue = geekList.fold(geekList[0],max); 
  
  // Printing the values 
  print("Smallest value in the list : $smallestGeekValue"); 
  print("Largest value in the list : $largestGeekValue"); 
}

Output:

Smallest value in the list : 3
Largest value in the list : 121

Answer from : https://www.geeksforgeeks.org/dart-finding-minimum-and-maximum-value-in-a-list/

Answer 3

If you don't want to import dart: math and still wants to use reduce:

main() {
  List list = [2,8,1,6]; // List should not be empty.
  print(list.reduce((curr, next) => curr > next? curr: next)); // 8 --> Max
  print(list.reduce((curr, next) => curr < next? curr: next)); // 1 --> Min
}

Answer 4

You can now achieve this with an extension as of Dart 2.6:

import 'dart:math';

void main() {
  [1, 2, 3, 4, 5].min; // returns 1
  [1, 2, 3, 4, 5].max; // returns 5
}

extension FancyIterable on Iterable<int> {
  int get max => reduce(math.max);

  int get min => reduce(math.min);
}

Answer 5

For empty lists: This will return 0 if list is empty, the max value otherwise.

  List<int> x = [ ];  
  print(x.isEmpty ? 0 : x.reduce(max)); //prints 0

  List<int> x = [1,32,5];  
  print(x.isEmpty ? 0 : x.reduce(max)); //prints 32