I am using request.path
to return the current URL in Django, and it is returning /get/category
.
I need it as get/category
(witho
Another one with regular expressions:
>>> import re
>>> s = "/get/category"
>>> re.sub("^/|/$", "", s)
'get/category'
def remove_lead_and_trail_slash(s):
if s.startswith('/'):
s = s[1:]
if s.endswith('/'):
s = s[:-1]
return s
Unlike str.strip()
, this is guaranteed to remove at most one of the slashes on each side.
>>> "/get/category".strip("/")
'get/category'
strip()
is the proper way to do this.